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skelet666 [1.2K]
3 years ago
5

A scientist wants to calculate the kinetic energy of a cheetah as it chases down its prey. What does the scientist need to measu

re in order to determine the kinetic energy of the cheetah?
Select all that apply.

the cheetah's amount of matter
the cheetah's speed
the amount of energy the cheetah absorbs from the sun
the amount of energy the cheetah releases into its surroundings
the cheetah's temperature
Physics
2 answers:
neonofarm [45]3 years ago
5 0

Answer:

the cheetah's amount of matter

the cheetah's speed

Explanation:

Kinetic energy is calculated according to the following equation

K.E = \frac{mv^{2} }{2}

where m represents the mass of the body in kilograms

and v represents the magnitude of the velocity which is know as speed of the body in m/s

Knowing this then, the scientist needs two things from that list:

the cheetah's amount of matter (also known as the mass)

the cheetah's speed

Feliz [49]3 years ago
4 0

Answer:

A + B

Explanation:

A) The cheetah's amount of matter

B) The cheetah's speed

(P.S. I just took a test on this and got it correct.)

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Answer:

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Explanation:

As we know that the formula of range is given as

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now we know that

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now we need to find such angles for which the range is half the maximum value

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Three packing crates of masses, M1 = 6 kg, M2 = 2 kg and M3 = 8 kg are connected by a light string of negligible mass that passe
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Using these diagram, we can set up a system of equations for the sum of forces in the x and y direction.

∑Fₓ = maₓ

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Let's start with the free body diagram for crate #2. Let's set the positive direction on top and the negative direction on the bottom. We can see that the forces acting on crate #2 are in the y-direction, so let's use Newton's 2nd Law to write this equation:

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Note that the tension and acceleration are constant throughout the system since the string has a negligible mass. Therefore, we don't really need to write the subscripts under T and a, but I am doing so just so there is no confusion.

Let's solve for T in the equation...

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We'll come back to this equation later. Now let's go to the free body diagram for crate #1.

We want to solve for the forces in the x-direction now. Let's set the leftwards direction to be positive and the rightwards direction to be negative.

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  • [m₁g cos(30) · 0.28] - [m₁g sin(30)] = m₁aₓ
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Now let's go back to this equation:

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We have 3 known variables and we can solve for the tension force.

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The tension force is the same throughout the string, therefore, the tension in the string connecting M2 and M3 is 39.81 N.

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