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Leni [432]
2 years ago
7

To reach a distance of 2 km, a car has to cover a path of 2.4 km in 10 minutes. Calculate its average speed and velocity

Physics
1 answer:
nexus9112 [7]2 years ago
5 0

Answer:

Average speed = <u>0.24 km/min.</u>

Average velocity = <u>0.2 km/min.</u>

Explanation:

<u>Finding average velocity</u> :

  • Least possible distance / Time taken
  • 2 km / 10 min
  • 0.2 km/min.

<u></u>

<u>Finding average speed</u> :

  • Path distance / Time taken
  • 2.4 km / 10 min
  • 0.24 km/min.
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Particles q1 = -53.0 uc, q2 = +105 uc, and
Nimfa-mama [501]

Answer:

-180.38\ \text{N}

Explanation:

q_1=-53\ \mu\text{C}

q_2=105\ \mu\text{C}

q_3=-88\ \mu\text{C}

r = Distance between the charges

r_{12}=0.5\ \text{m}

r_{23}=0.95\ \text{m}

r_{13}=1.45\ \text{m}

k = Coulomb constant = 9\times 10^9\ \text{Nm}^2/\text{C}^2

Net force is given by

F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}

The force on the particle q_1 is -180.38\ \text{N}.

8 0
3 years ago
I need help with this one ! <br><br>Explanation needed ~ ​
weqwewe [10]

Answer:

Please find here some hints :

Rule. Newton’s second law, or fundamental principle of dynamics, mentions that a resultant force exerted on an object is always equal to the product of the mass of that object by its acceleration. ... Each force applied to an object causes this object to accelerate in the direction of the force applied.

Is acceleration a force?

The acceleration force, sometimes called the inertia force, is the vehicle’s resistance to speed variations. It holds you back when you increase your speed and pushes you back when you slow down.

Explanation:

5 0
2 years ago
What is gravitational field intensity?​
mezya [45]

<h3>Answers :</h3>

The gravitational field intensity (EG) or (g) is the force on a unit mass at a point in the field.  

Since the force (F) on a body of mass m in a gravitational field of a body of mass M = GMm/r2 .

you can see that the force per unit mass is given by F/m. So:

Gravitational Field Intensity (EG) = (g) = F/m = GM/r2

The units for EG are N kg -1 or since F = ma, F/m = a and so EG may be expressed in ms -2

Hope this will help you :))

Do give this answer a brainliest :D

7 0
3 years ago
HELP IM IN A EXAM!!!
natali 33 [55]
Answer:

Species A and C

Explanation: none
8 0
3 years ago
Read 2 more answers
Amy is in-line skating. Her mass is 50 kg. She is rolling forward (north) on a flat section of road at 10 m/s. The rolling frict
Licemer1 [7]

Answer:

The right solution is "0.50 m/s²". A further explanation is provided below.

Explanation:

The given values are:

Mass,

m = 50 kg

Speed,

v = 10 m/s

Rolling friction acting backward (south),

f = 10 N

Air resistance acting backward (south),

F_T = 15 N

The total force acting will be:

⇒  F = -f-F

On substituting the given values, we get

⇒      =-10-15

⇒      =-25 \ N

Now,

⇒  a = \frac{F}{m}

On substituting the given values, we get

⇒     =\frac{-25}{50}

⇒     =-0.50 \ m/s^2

The horizontal acceleration will be "0.50 m/s²" because the (-)ve sign indicates it in south direction.

4 0
3 years ago
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