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AnnZ [28]
3 years ago
5

Which of the following would reduce the resistance of a metal wire?

Physics
1 answer:
MAVERICK [17]3 years ago
3 0
I think A. increasing thickness, i hope i help :)

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suter [353]

Answer:

Onel de guzman now he's 44,the first world's computer virus has admitted to his guilt.

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how does the electric force between two charged particles change if the distance between them is increased by a factor of 3? a.
Aleksandr [31]

how does the electric force between two charged particles change if the distance between them is increased by a factor of 3?

a. it is reduced by a factor of 3

4 0
3 years ago
Consider a horizontal layer of the dam wall of thickness dx located a distance x above the reservoir floor. what is the magnitud
sergejj [24]
The force on the layer will be equivalent to the weight of water on it. This is given by:
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3 years ago
Read 2 more answers
An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the
Lerok [7]
Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:


Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s


The velocity is negative, because the object is thrown downwards
7 0
2 years ago
You have a grindstone (a disk) that is 90.0 kg, has a 0.340-m radius, and is turning at 90.0 rpm, and you press a steel axe agai
QveST [7]

Answer:

Explanation:

Given mass of grindstone m=90\ kg

radius of stone r=0.34\ m

angular speed of disc \omega =90\ rpm

Steel Axle applying a force of F=20\ N

coefficient of kinetic friction \mu =0.2

Frictional Torque applied by steel is given by

\tau=r\times f_r

\tau =r\times \mu F

where f_r=frictional force

\tau =r\times \mu \times F

\tau =0.34\times 0.2\times 20

\tau =1.36\ N-m

Torque is also given by

\tau =I\cdot \alpha

where \alpha=angular acceleration

I=moment of Inertia

\tau =0.5Mr^2\times \alpha

0.5Mr^2\times \alpha =1.36\ N-m

0.5\times 90\times 0.34^2\times \alpha =1.36

\alpha =0.261\ rad/s^2

3 0
3 years ago
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