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lana66690 [7]
3 years ago
5

List down the procedures for each swimming stroke 1.Crawl 2.Breaststoke 3.Butterflystroke 4. Backstoke​

Physics
1 answer:
Elena L [17]3 years ago
4 0

Answer: Swimming strokes are techniques that includes arm and leg movements to help push the swimmer against water and propel the swimmer forward.

Explanation:

There are different types of swimming strokes these includes:

--> FRONT CRAWL: This is the fastest of all the techniques. The procedure includes:

• the body is kept flat, facing down and in line with the water surface,

• As the swimmer proceeds with movements, the arms are alternately moved in a PULL (with your palms facing down pull in line with the body) and RECOVERY (with the hand closed to the upper thigh, lift one arm out of the water with a bent elbow) actions.

• As you finish the recovery phase, turn quickly side ways to take in some air.

• With ankles relaxed and flexible, point your toes behind you and kick up-and-down in a continuous motion from your thighs.

BUTTERFLY STROKE: The procedures for this technique includes:

• the body is kept flat, facing down and in line with the water surface.

• the arms are moved in three ways, the catch, pull and recovery movements. The Catch involves the arms being straight, shoulder width apart and palms facing down wards, press down and out against the water with both hands at the same time. The pull involves the hands being pulled towards the body in a semicircular motion. The recovery starts at the end of each pull, the arms are moved out and over the water simultaneously and is thrown forward into the starting position.

• the chin is being raised up at the recovery stage to draw in a breath while looking straight.

• With both legs together and toes pointed, kick downwards at the same time.

• the body is moved in a wave-like manner.

BREASTSTROKE: The procedure for this technique includes;

• the body is kept flat, facing down and in line with the water surface

• the arms are also moved in three ways. In the catch movements, with arms out straight and palms facing downwards, press down and out at the same time. With elevated elbows above the arms, pull hard towards the chest. Then while recovering, to reduce drag when pushing against water, the both palms are joined together Infront of the chest and pushed out until the arms are straight again.

• the head is lifted above water at the end of pulling movement to breath in air.

• bend your knees to bring your heel towards your bottom and make a circular motion outwards with your feet until they return to the starting position.

BACKSTROKE: The procedure for this technique includes

• the body kept flat while backing the water surface. But following the arm movement, it rows from side to side.

• the arms performs alternating and opposite movements. As one arm pulls backwards in the water the other arm recovers above the water.

• taking in air should be alternated with the arm movements.

• the legs are moved up and down in a quick succession to enhance movements.

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Answer:

<u>Part A:</u>

Unknown variables:

velocity of the astronaut after throwing the tank.

maximum distance the astronaut can be away from the spacecraft to make it back before she runs out of oxygen.

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mass of the astronaut after and before throwing the tank.

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Where:

mt = mass of the tank

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va = velocity of the astronaut

To obtain the maximum distance the astronaut can be away from the spacecraft we use this equation:

x = x0 + v · t

Where:

x = position of the astronaut at time t.

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The maximum distance the astronaut can be away from the spacecraft is 162 m.

Explanation:

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Due to conservation of momentum, the momentum of the oxygen tank when it is thrown away must be equal to the momentum of the astronaut but in opposite direction. In other words, the momentum of the system astronaut-oxygen tank is the same before and after throwing the tank.

The momentum of the system before throwing the tank is zero because the astronaut is at rest:

Initial momentum = m · v

Where m is the mass of the astronaut plus the equipment (100 kg) and v is its velocity (0 m/s).

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initial momentum = 0

After throwing the tank, the momentum of the system is the sum of the momentums of the astronaut plus the momentum of the tank.

final momentum = mt · vt + ma · va

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mt = mass of the tank

vt = velocity of the tank

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va = velocity of the astronaut

Since the initial momentum is equal to final momentum:

initial momentum = final momentum

0 = mt · vt + ma · va

- mt · vt = ma · va

Now, we have proved that the momentum of the tank must be equal to the momentum of the astronaut but in opposite direction.

Solving that equation for the velocity of the astronaut (va):

- (mt · vt)/ma = va

mt = 15 kg

vt = 10 m/s

ma = 100 kg - 15 kg = 85 kg

-(15 kg · 10 m/s)/ 85 kg = -1.8 m/s

The velocity of the astronaut is 1.8 m/s in direction to the spacecraft.

Let´s place the origin of the frame of reference at the spacecraft. The equation of position for an object moving in a straight line at constant velocity is the following:

x = x0 + v · t

where:

x = position of the object at time t.

x0 = initial position.

v = velocity.

t = time.

Initially, the astronaut is at a distance x away from the spacecraft so that

the initial position of the astronaut, x0, is equal to x.

Since the origin of the frame of reference is located at the spacecraft, the position of the spacecraft will be 0 m.

The velocity of the astronaut is directed towards the spacecraft (the origin of the frame of reference), then, v = -1.8 m/s

The maximum time it can take the astronaut to reach the position of the spacecraft is 1.5 min = 90 s.

Then:

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1.8 m/s · 90 s = x

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The maximum distance the astronaut can be away from the spacecraft is 162 m.

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(b) The plane is parallel to the xy-plane.

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(c) The plane contains the y-axis, and its normal makes an angle of 35.0° with the x-axis.

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3 years ago
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