The number of wavelengths that pass a point each per second is:

With its wheels locked, a van slides down a hill inclined at 40.0° to the horizonta l. Find the acceleration of this van A) if t

andreyandreev [35.5K]

Answer:

Explanation:

Check attachment for solution

7 0

3 years ago

Choose two forces and compare and contrast these forces. These must be different forces than used in the prior question. Provide

marin [14]

Answer:

Explanation:

There are 4 forces. These are 1) Gravity, 2) Weak Nuclear Force, 3) Electromagnetism, and 4) Strong Nuclear Force.

Order of strength from weakest to strongest: Gravity, Weak Nuclear Force, Electromagnetism, Strong Nuclear Force

Type of Range:

Gravity - Unlimited range

Weak Nuclear Force - Limited range

Electromagnetism - Infinite range

Strong Nuclear Force - Limited Range

Found in:

Gravity - Exists between all objects with mass

Weak Nuclear Force - Governs over beta decays like the emission of electron or positron

Electromagnetism - the attraction found between particles that are electrically charged

Strong Nuclear Force - Found in atoms and subatomic particles. It is responsible for holding the atoms' nucleus together.

6 0

3 years ago

What must the charge (sign and magnitude) of a particle of mass 1.41 gg be for it to remain stationary when placed in a downward

Yuri [45]

Answer:

$q = 2.067 \times 10^{-5}\ C$

Explanation:

Given,

mass = 1.41 g = 0.00141 Kg

Electric field,E = 670 N/C.

We know,

Force in charge due to Electric field.

F = E q

And also we know

F = m g

Equating both the equation of motion

m g = E q

$q =\dfrac{mg}{E}$

$q =\dfrac{0.00141 \times 9.81}{670}$

$q = 2.067 \times 10^{-5}\ C$

Charge of the particle is equal to $q = 2.067 \times 10^{-5}\ C$

6 0

3 years ago

A slender, uniform metal rod of mass M and length lis pivoted without friction about an axis through its midpoint andperpendicul

lys-0071 [83]

Answer:

Explanation:

Moment of inertia of the metal rod pivoted in the middle

= M l² / 12

If the spring is compressed by small distance x twisting the rod by angle θ

restoring force by spring

= k x

moment of torque about axis

= k x l /2

= k θ( l /2 )² ( x / .5 l = θ )

=

moment of torque = moment of inertia of rod x angular acceleration

k θ( l /2 )² = M l² / 12 d²θ/dt²

d²θ/dt² = 3 k/M θ

acceleration = ω² θ

ω² = 3 k/M

ω = √ 3 k / M

8 0

3 years ago

Read 2 more answers

Two loudspeakers placed 8.0 m apart are driven in phase by an audio oscillator whose frequency range is 2.2 kHz to 2.9 kHz. A po

My name is Ann [436]

Answer:

The answer to the question is 2.2khz

Explanation:

Let z₁ = 5.4m

Let z₂ = 4.6m

The path difference Δz = z₁-z₂ = 5.4 - 4.6 = 0.8m

For the interference= Δz λ, 2λ, 3λ......

The wavelength λ = 0.8m

The speed of sound v = 344m/s

The frequency f = v/λ = 344/0.8 = 430hz

Now,

f₁ =f, f₂= 2f, f₃ = 3f, f₄= 4f, f₅ =5f which is,

f₁ =f = 430Hz, f₂=2f =860Hz, f₃ =3f =1290Hz f₄ =4f =1720Hz and f₅=5f =2150Hz

f5 = 2120Hz = 2.200Hz

we will convert to two significant figures =2.2kHz

8 0

3 years ago