Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
Answer:
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Answer:
20m/s
Explanation:
acceleration=final velocity-initial velocity/time
4.0m/s²=v m/s-0m/s/5.0sec
5.0sec×4.0m/s²=v m/s-0m/s×5.0m/s/5.0m/s
20m/s=v
The crowbar is placed under a small edge under the top of the box. The crowbar will send the box lid flying from the opposite direction that the crowbar is placed. Please give Brainlest if you understand.
The correct answer is c because B) is a vector which includes both velocity and direction
