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iren2701 [21]
3 years ago
7

While a balloon is being filled, if the temperature of the air in the balloon decreases, what happens to its volume?

Physics
2 answers:
andre [41]3 years ago
6 0

Answer: It decreases

Explanation:

Charle's Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T     (At constant pressure and number of moles)

{V_1\times T_1}={V_2\times T_2}

where,

V_1 = initial volume of gas  

V_2 = final volume of gas

T_1 = initial temperature of gas

T_2 = final temperature of gas

Therefore, as volume and temperature are proportional, if the temperature of the air in the balloon decreases,  its volume also decreases.

Ugo [173]3 years ago
4 0
Why is it always balloons?
anyways so the balloon volume goes somewhere else when it shrinks because the balloon is losing air i think
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Answer:

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Explanation:

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q_1=q_2 = Charge of electron and proton = 1.6\times 10^{-19}\ C

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Force is given by

F=\dfrac{kq_1q_2}{r^2}\\\Rightarrow F=\dfrac{8.99\times 10^9\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{(997\times 10^{-9})^2}\\\Rightarrow F=2.31531\times 10^{-16}\ N

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The area of the velocity time graph gives displacement of the body true or false?
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The area of the velocity time graph gives displacement of the body true or false?

The answer this is true.

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A 53 kg crate is at rest on a level floor, and the coefficient of kinetic friction is 0.36. The acceleration of gravity is 9.8 m
tino4ka555 [31]

Answer:

42.6 m

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Force, F = 372.098 N

Net force, f = F - friction force

f = 372.098 - μ m x g = 372.098 - 0.36 x 53 x 9.8

f = 185.114 N

acceleration, a = f / m = 185.114 / 53 = 3.49 m/s^2

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s = ut + 1/2 at^2

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A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni
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The magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

The given parameters;

  • <em>length of the solenoid, L = 91 cm = 0.91 m</em>
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The magnitude of the magnetic field inside the solenoid is calculated as;

B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\

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\mu_o is the permeability of frees space = 4π x 10⁻⁷ T.m/A

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Thus, the magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

Learn more here:brainly.com/question/17137684

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