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3 years ago

While a balloon is being filled, if the temperature of the air in the balloon decreases, what happens to its volume?

Physics

2 answers:

andre [41]3 years ago

6 0

Answer: It decreases

Explanation:

Charle's Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles)

${V_1\times T_1}={V_2\times T_2}$

where,

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

$T_1$ = initial temperature of gas

$T_2$ = final temperature of gas

Therefore, as volume and temperature are proportional, if the temperature of the air in the balloon decreases, its volume also decreases.

Ugo [173]3 years ago

4 0

Why is it always balloons?
anyways so the balloon volume goes somewhere else when it shrinks because the balloon is losing air i think

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True or false the potential energy of a freely object increases as it begins to fall

Eva8 [605]

False, as an object falls its potential energy turns into kinetic energy thus decreasing the potential energy.

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3 years ago

Water inside a tub rises from 15 mL to 19 mL when an object is submerged. If the mass of the object is 249, what's the density o

Alex_Xolod [135]

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 249 g

volume = final volume of water - initial volume of water

volume = 19 - 15 = 4 mL

We have

$density = \frac{249}{4} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

The work-energy theorem states that a force acting on a particle as it moves over a ______ changes the ______ energy of the part

ololo11 [35]

Answer:

distance/ kinetic

Explanation:

According to the work energy theorem, the work done by all forces is equal to the change in kinetic energy of the body.

So, As the force is applied in the same direction of the distance traveled,so only the kinetic energy of the body changes as after application of force, the speed of the body changes.

6 0

3 years ago

A 1.0 × 10^3 kg sports car is initially traveling at 15 m/s. The driver then applies the brakes for several seconds so that -25

algol13

Answer:

Ea = 112500[J]

Eb = 87500[J]

Explanation:

To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.

This can be easily visualized by the following equation:

$E_{A}+E_{friction}=E_{B}$

Now we must define the energies at points A & B.

<u>For point A</u>

At point A we only have kinetic energy since it moves at 15 [m/s]

So the kinetic energy

$E_{A}=\frac{1}{2}*m*v_{A}^{2} \\E_{A}=\frac{1}{2} *1000*(15)^{2} \\E_{A}=112500[J]$

The final kinetic energy can be calculated as follows:

$112500-25000=E_{B}\\E_{B}=87500[J]$

8 0

3 years ago

A 2.00-kg ball is moving at 2.20 m/s toward the right. It collides elastically with a 4.00-kg ball that is initially at rest. 1)

loris [4]

Elastic collision is when kinetic energy before = kinetic energy after

Ek= 1/2mv^2

total before
Ek=1/2(2)(2.2^2) = 4.84 J

total after
Ek= 1/2(2+4)(v^2) = 3v^2

Before = after
4.84=3v^2 | divide by 3
121/75 = v^2 | square root both sides
v=1.27 m/s

7 0

3 years ago