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serg [7]
3 years ago
12

You input 75 J of work with a wedge. If the wedge does 65 J of useful work, what if the efficiency of the wedge ?

Physics
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

Efficiency of wedge is the ratio of "work done by the machine to the work supplied to the machine".

           Efficiency (η) = Work done by machine ÷ Work supplied

                                  = 65 ÷ 75

                                 = 0.86%

<em>Efficiency of wedge is 86%</em>

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If a cart of a roller coaster has a mass of 250kg and is at a height of 14 meters. What is the cart's potential energy?
ahrayia [7]

Answer:

3430000 J

Explanation:

The formula for potential energy is PE=mgh.

M being the mass, g being the force of gravity, and h being the height.

First thing you want to do is convert 250 kg to g (grams).

From there you get 25000g and you have to multiply that by 14m and 9.8m/s^2 (the force of gravity is constant, at least on earth).

5 0
3 years ago
What is the standard measurement system used by scientists around the world?
sleet_krkn [62]

Answer:

Hey mate....

Explanation:

This is ur answer....

<h3><em>The International System of Units (SI), commonly known as the metric system, is the international standard for measurement.</em></h3>

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5 0
2 years ago
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Jupiter's gravity is about 2.3 times stronger than Earth's gravity. Calculate the
AlexFokin [52]

Answer:

Explanation:

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4 0
2 years ago
The current in a microwave oven is 6.16 A .
rjkz [21]

Answer:

v = I xR =6.16 × 17.6 = 108.416 v

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6 0
3 years ago
Parallel conducting tracks, separated by 2.20 cm, run north and south. There is a uniform magnetic field of 1.20 T pointing upwa
mars1129 [50]

Answer:

The magnitude of the magnetic force on the rod is 0.037 N.

Explanation:

The magnetic force is given by:

F = qvBsin(\theta)

Since the charge (q) is:

q = I*t

Where<em> I</em> is the current = 1.40 A, and <em>t</em> the time  

And the speed (v):

v = \frac{L}{t}

Where <em>L </em>is the tracks separation = 2.20 cm = 0.022 m

Hence, the magnetic force is:

F = ILBsin(\theta)

Where <em>B </em>is the magnetic field = 1.20 T and <em>θ</em> is the angle between the tracks and the magnetic field = 90°

F = ILBsin(\theta) = 1.40*0.022*1.20*sin(90) = 0.037 N

Therefore, the magnitude of the magnetic force on the rod is 0.037 N.

I hope it helps you!

5 0
2 years ago
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