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serg [7]
3 years ago
12

You input 75 J of work with a wedge. If the wedge does 65 J of useful work, what if the efficiency of the wedge ?

Physics
1 answer:
zavuch27 [327]3 years ago
5 0

Answer:

Efficiency of wedge is the ratio of "work done by the machine to the work supplied to the machine".

           Efficiency (η) = Work done by machine ÷ Work supplied

                                  = 65 ÷ 75

                                 = 0.86%

<em>Efficiency of wedge is 86%</em>

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Geology belongs to which main category of science?
sergey [27]
Geology belongs to the category of Natural Sciences. Natural sciences is the study of natural phenomena. Among the natural sciences, we have physical science, which is the study of non-living systems. Further along this branch, we have earth sciences where Geology belongs.
7 0
3 years ago
Can something have energy without having momentum? explain. can something have momentum without having energy? defend your answe
marta [7]
Momentum  is a product mass and velocity. If a certain object posses a kinetic energy, then it should have a momentum since it is moving which has a velocity. However, if the object is at rest and only has potential energy, then it would not have momentum. So, for the first question the answer would be yes, an object can have energy without having any momentum. For the second question, every object whether it is moving or at rest, possess some energy, potential for an object at rest and kinetic for an object that is moving. Thus, the answer would be no, an object having momentum would always have energy.
8 0
3 years ago
A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a
IrinaK [193]

The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

To find the answer, we need to know about the time of flight and range of projectile motion.

<h3>What's the expression of range of a projectile motion?</h3>
  • Range = U²× sin(2θ)/g
  • U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
  • U=√{Range×g/sin(2θ)}
  • Here, range= 2.20m, = 36.5°
  • U= √{2.20×9.8/sin(73)}

U= √{2.20×9.8/sin(73)} = 22.5m/s

<h3>What's the expression of time of flight in projectile motion?</h3>
  • Time of flight= (2×U×sinθ)/g
  • So, T= (2×22.5×sin36.5°)/9.8

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

#SPJ1

4 0
2 years ago
The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol
Lesechka [4]

Answer:

\Delta V = 0.053 A

Explanation:

Electric field in a given region is given by equation

E = \frac{A}{r^4}

as we know the relation between electric field and potential difference is given as

\Delta V = -\int E. dr

so here we have

\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

r_1 = 1.71 m  and r_2 = 2.89 m

so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

8 0
3 years ago
11111111111111111111
Lady bird [3.3K]

Answer:

Explanation:

boiii

8 0
3 years ago
Read 2 more answers
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