Triangle ABC is an isosceles triangle.
Solution:
Given data:
AB is parallel to CD and AC is the transversal.
∠ABC = 70° and ∠ACD = 55°
<em>If two parallel lines are cut by a transversal, then alternate interior angles are congruent.</em>
∠BAC ≅ ∠ACD
m∠BAC = m∠ACD
m∠BAC = 55°
<em>Sum of the angles in a straight line = 180°</em>
m∠ACD + m∠ACB + m∠ABC = 180°
55° + m∠ACB + 70° = 180°
m∠ACB + 125° = 180°
Subtract 125° from both sides, we get
m∠ACB = 55°
In triangle ABC,
∠BAC = 55° and ∠ACB = 55°
∠BAC = ∠ACB
<em>Two angles in the triangle are equal. </em>
Therefor triangle ABC is an isosceles triangle.
Answer: A & C
Step-by-step explanation:
You can also simplify the above by taking the -4 out of the radical
It becomes 2 x 
, which can be simplifed to C
Answer:
Step-by-step explanation:
32 tubes of yellow paint is needed
We can find h by calculating the area S of the parallelogram in two ways. We can write:
. On the other hand,
. Then:
It is A so you have it right
