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babymother [125]
3 years ago
6

Which scientist established the law of octaves?

Physics
1 answer:
Alchen [17]3 years ago
5 0
<span>The correct answer is John Alexander Reina Newlands. He established the law of octaves which basically set the elements according to their atomic number and grouped them according to their physical and chemical properties. His ideas were used later in creation of the periodic laws and the periodic table of elements.</span>
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¿Cuáles son los fenómenos que no se pueden explicar con la teoría corpuscular de la luz?
maxonik [38]
The answer is diffraction or interference
5 0
3 years ago
An object is pulled with a 85 N force inclined at 27° along a horizontal surface ABC
OLEGan [10]

Answer:

m = 15.15 kg

Explanation:

Newton's Second Law of motion states that when an unbalanced force is applied on a body, an acceleration is produced in it in the direction of force. The component of force along the horizontal direction here, will be given by the Newton's Second Law as:

Fx = ma

F Cosθ = ma

where,

F = Magnitude of Force = 85 N

θ = Angle with horizontal = 27°

m = mass of object = ?

a = acceleration of object = 5 m/s²

Therefore,

85 N Cos 27° = m(5 m/s²)

m = 75.73 N/5 m/s²

<u>m = 15.15 kg</u>

6 0
3 years ago
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Jlenok [28]

Answer:

Explanation:OFC!!!

3 0
3 years ago
Read 2 more answers
A block, whose mass is 0.500 kg, is attached to a spring with a force constant of 126 N/m. The block rests upon a frictionless,
erastova [34]

Answer:

(a) F = 15.12 N

(b) a = 30.24 m/s²

(c) To Left

Explanation:

(a)

The magnitude of the spring force is given by Hooke's Law as follows:

F = kx

where,

F = Spring Force = ?

k = Spring Constant = 126 N/m

x = Displacement = A = 0.12 m

Therefore,

F = (126 N/m)(0.12 m)

<u>F = 15.12 N</u>

(b)

The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:

F = ma

where,

F = Spring Force = 15.12 N

m = mass of block = 0.5 kg

a = magnitude of acceleration = ?

15.12 N = 0.5 kg (a)

a = 15.12 N/0.5 kg

<u>a = 30.24 m/s²</u>

<u></u>

(c)

Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be <u>to left.</u>

8 0
3 years ago
Se deja resbalar por un plano inclinado de 30° un cuerpo de 15kg. Calcular la aceleración con la que desciende suponiendo que no
kupik [55]

Answer:

4.9 m/s^2

Explanation:

In order to find the acceleration of the block, we have to find the net force acting on it along the direction parallel to the incline.

However, there is only one force acting on the block along this direction: it is the component of the weight parallel to the plane, given by

mg sin \theta

where

m = 15 kg is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

\theta=30^{\circ} is the angle of the incline

According to Newton's second law, the net force is proportional to the acceleration, a:

F=ma

So we can write:

ma = mg sin \theta

And so, the acceleration is:

a=g sin \theta = (9.8)(sin 30^{\circ})=4.9 m/s^2

7 0
3 years ago
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