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11111nata11111 [884]

4 years ago

12

How is the current controlled for a given voltage

1 answer:

Leni [432]4 years ago

6 0

Answer:

The current can be controlled by modifying the resistance value

Explanation:

The current can be controlled by modifying the resistance value, usually a variable resistance device called potentiometer is used. This can be observed mathematically using the ohm law which is defined as voltage equal to the current product by resistance.

V = I*R

where:

I = current [amp]

R = resistance [ohm]

V = voltage [volt]

We can see that if we reduce the resistance the current will be increased

I = v / R

And if we amplify the resistance (R) the current will be diminished

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A horizontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axle through the center

Andrei [34K]

Answer:

The angular speed is $\omega_2= 3.81s^{-1}$ .

Explanation:

The law of conservation of angular momentum says that for an isolated system

$I_1\omega_1 = I_2 \omega_2$

Now, when the student is at the rim of the platform the moment of inertia of the system is

$I_1 = mr_1^2+275kg\cdot m^2$

$I _1 = (62.3kg)(3.22m)^2+275kg\cdot m^2$

$I_1 = 920.95kg\cdot m^2$ ,

and the angular speed is

$\omega_1 = 1.33s^{-1}$ .

When the student is $r_2 = 0.861m$ from the center,the moment of inertia of the system becomes

$I_2 =mr_2^2+275kg\cdot m^2$

$I_2 =(62.3kg)(0.861m)^2+275kg\cdot m^2$

$I_2= 321.18kg\cdot m^2$

Thus, from conservation of angular momentum

$(920.95kg\cdot m^2)(1.33s^{-1})= (321.18kg\cdot m^2)\omega_2$

$\omega_2=\dfrac{ (920.95kg\cdot m^2)(1.33s^{-1})}{(321.18kg\cdot m^2)}$

$\boxed{\omega_2= 3.81s^{-1}}$

which is the angular speed when the student is 0.861 meters from the center.

3 0

3 years ago

During a power outage, people use generators. What does a geneszitor dia?

stepladder [879]

Kinetic to Electric
Hope this helped good luck!

7 0

3 years ago

In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi

Georgia [21]

components of the speed of the coin is given as

$v_x = v cos60$

$v_x = 6.4 cos60 = 3.2 m/s$

$v_y = vsin60$

$v_y = 6.4 sin60 = 5.54 m/s$

now the time taken by the coin to reach the plate is given by

$t = \frac{\delta x}{v_x}$

$t = \frac{2.1}{3.2}$

$t = 0.656 s$

now in order to find the height

$h = vy * t + \frac{1}{2} at^2$

$h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2$

$h = 1.52 m$

so it is placed at 1.52 m height

3 0

3 years ago

What causes an electric force?

Fantom [35]

Answer:

Electric force results form mutual interactions between two charges.

7 0

3 years ago

A concave mirror is diverging mirror.true or false

marissa [1.9K]

Answer:

true

Explanation:

it is concave when it diverging

4 0

3 years ago