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maria [59]
3 years ago
10

What is the relationship between the planets and other astronomical bodies?

Physics
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

Hierarchical relationships between planets and other astronomical bodies

Explanation:

Hierarchical is the relationships between planets and other astronomical bodies relative to solar system, galaxy, and universe, including distance, size, and composition. ... Gravity and energy influence the formation of galaxies, including our own Milky Way Galaxy, stars, the planetary systems, and Earth.

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A. 36 mins 52.5 secs<br> b. 24mins 22.5 secs<br> c. 13 mins 0 secs<br> d. 9 mins 45 secs
DedPeter [7]
I think it might be A. I’m sorry if I’m wrong
5 0
3 years ago
Read 2 more answers
Calculate the individual positive plate capacity in motive power cell that has 15 plates and a copa of 595 Ah A. 110 Ah B. 75 Ah
Sphinxa [80]

Answer:

The individual positive plate capacity is 85 Ah.

(D) is correct option.

Explanation:

Given that,

Number of plates = 15

Capacity = 595 Ah

We need to calculate the individual positive plate capacity in motive power cell

We have,

15 plates means 7 will make pair of positive and negative.

So, there are 7 positive cells individually.

The capacity will be

capacity =\dfrac{power}{number\ of\ cells}

Put the value into the formula

capacity =\dfrac{595}{7}

capacity =85\ Ah

Hence, The individual positive plate capacity is 85 Ah.

6 0
4 years ago
Read 2 more answers
Ashley is flying a plane that has to reach a gradient of 360m/km in order to take off and not crash. Her goal is to travel from
KengaRu [80]

Answer:

She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing

Explanation:

The given parameters are;

The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km

The initial elevation of the plane Ashley is flying = Sea level = 0 m

The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance

∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance

We have;

The gradient  = Rate of change of elevation/(Horizontal distance)

Therefore;

The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km

The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.

6 0
3 years ago
You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While
ANTONII [103]

To solve this problem it is necessary to apply the concepts related to the Rotational Force described from the equilibrium and Newton's second law.

When there is equilibrium, the Force generated by the tension is equivalent to the Force of the Weight. However in rotation, the Weight must be equivalent to the Centrifugal Force and the tension, in other words:

W = F_T + m\omega^2r_E

Where

\omega = \frac{2\pi}{T} \rightarrow Angular velocity is equal to the Period, at this case Earth's period

r_E = 6.371*10^6m \rightarrow Radius of the Earth

m = mass

F_T= Force of Tension

W = mg \rightarrow Newton's second law

Replacing and re-arrange to find the Tension we have,

F_T = W- \frac{W}{g} (\frac{2\pi}{T})^2r_E

F_T = W(1-(\frac{2\pi}{T})^2\frac{r_E}{g})

F_T = (505)(1-(\frac{2\pi}{24hours})^2\frac{6.371*10^6}{9.8})

F_T = (505)(1-(\frac{2\pi}{24hours(\frac{3600s}{1hour})})^2\frac{6.371*10^6}{9.8})

F_T = (505)(1-(\frac{2\pi}{86400})^2\frac{6.371*10^6}{9.8})

F_T = 503.26N

Therefore when Sneezy is on the equator he is in a circular orbit with a Force of tension of 503.26N

7 0
3 years ago
A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of
tester [92]

Answer:

θ₂ = 35.26°

Explanation:

given,

refractive index of air, n₁ = 1

refractive index of glass, n₂ = 1.5

angle of incidence, θ₁ = 60°

angle of refracted light, θ₂ = ?

using Snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1 x sin 60° = 1.5 sin θ₂

sin θ₂ = 0.577

θ₂ = sin⁻¹(0.577)

θ₂ = 35.26°

Hence, the refracted light is equal to  θ₂ = 35.26°

7 0
3 years ago
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