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maxonik [38]
3 years ago
5

A substance with a ph of 9 has

Chemistry
1 answer:
Arisa [49]3 years ago
4 0

Answer:

c) more OH⁻ ions than H₃O⁺ ions

Explanation:

A substance with a PH of 9 implies that it has more OH⁻ ions than H₃O⁺ ions.

Such substances are said to be an alkaline or a base.

A base is a substance the produces excess hydroxyl ion in aqueous solutions.

An acid will produce excess hydroxonium ions in a solution.

So, the pH scale is used to indicate whether a substance is an acid or base or non of them.

Acids have pH of less than 7

Bases have pH of > 7

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What is the final pH of a solution when 0.1 moles of acetic acid is added to water to a final volume of 1L?
kicyunya [14]

Answer:

The pH of solution is 2.88 .

Explanation:

The reaction is :

CH_3COOH-->CH_3COO^-+H^+

We know, K_a for this reaction is = 1.76\times 10^{-5}.

Also, since volume of water is 1 L.

Therefore, molarity of solution is equal to number of moles.

Also, K_a=\dfrac{[CH_3COO^-][H^+]}{[CH_3COOH]}

Let, amount of CH_3COO^- and\ H^+ produce is x.

So,

K_a=\dfrac{[x][x]}{[0.1]}\\1.76\times 10^{-5}=\dfrac{[x][x]}{[0.1]}

x=0.0013\ mol.

We know, pH=-log{x}=-log(0.0013)=2.88

Therefore, pH of solution is 2.88 .

Hence, this is the required solution.

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3 years ago
The "bleaching" of plant leaves is caused by: A.water pollution B.poor soil quality C.air pollution D.excess bacteria
devlian [24]

Answer: The "bleaching" of plant leaves is caused by air pollution.

8 0
3 years ago
Please help (20 points)
AlekseyPX

Answer:

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4 0
3 years ago
List the ways in which tadpole and frogs differ from each other?
Vera_Pavlovna [14]
<span>Tadpoles are developing into being frogs. They have yet to develop hind legs and have a tail.</span>
3 0
3 years ago
Read 2 more answers
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
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