Answer : The change in molar entropy of the sample is 10.651 J/K.mol
Explanation :
To calculate the change in molar entropy we use the formula:
where,
= change in molar entropy
n = number of moles = 1.0 mol
= final temperature = 300 K
= initial temperature = 273 K
= heat capacity of chloroform = 
Now put all the given values in the above formula, we get:
![\Delta S=1.0\times [91.47\ln T+7.5\times 10^{-2}T]^{300}_{273}](https://tex.z-dn.net/?f=%5CDelta%20S%3D1.0%5Ctimes%20%5B91.47%5Cln%20T%2B7.5%5Ctimes%2010%5E%7B-2%7DT%5D%5E%7B300%7D_%7B273%7D)
Therefore, the change in molar entropy of the sample is 10.651 J/K.mol
Answer:
4 is the correct answer since that belongs to one of his postulates.
Density = 760 g / 84 cm<span>³ = 9.0476 g/cm³</span>
Answer:
specific heat.
Explanation:
Definition:
The amount of heat required to raise the temperature of one gram of substance by one degree is called specific heat.
Formula:
Q = m. c. ΔT
Q = amount of heat required
m = mass of substance
c = specific heat of substance
ΔT = change in temperature
The substance with greater value of specific heat require more heat to raise the temperature while the substance with lower value will raise its temperature very quickly by absorbing smaller heat.
For example the beach sand gets hot very quickly because of lower specific heat of sand while water is colder than sand because of higher specific heat capacity.
