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dimulka [17.4K]
3 years ago
5

Current nuclear reactors use a process of controlled _____. fission fusion

Chemistry
2 answers:
Zinaida [17]3 years ago
6 0
The answer would be fission.

We have not yet been able to find an element capable of withstanding the massive heat from a fusion reaction. Fusion reactions are what occurs in stars.
valentina_108 [34]3 years ago
3 0
I do believe the answer is Fission.

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Is air a compound mixture or a element.
GenaCL600 [577]

Is air a compound mixture or a element. compound

8 0
3 years ago
Read 2 more answers
If 1 kg of fuel is used in the above fusion reaction (2 1H + 3 1H--> 4 2He+1 0N) , the resulting helium has a mass of 0.993 k
enot [183]
Δmc
2

For one reaction:
Mass Defect =Δm
=2(m
H
​
)−m
He
​
−m
n
​

=2(2.015)−3.017−1.009
=0.004 amu
1 amu=931.5 MeV/c
2

Hence,
E=0.004×931.5 MeV=3.724 MeV
E=3.726×1.6×10
−13
J=5.96×10
−13
J

For 1 kg of Deuterium available,
moles=
2g
1000g
​
=500
N=500N
A
​
=3.01×10
26

Energy released =
2
N
​
×5.95×10
−13
J
=8.95×10
13
6 0
2 years ago
Why is the endocrine system important?
Zepler [3.9K]
The endocrine system is important to the function of the human body because, endocrine glands release hormones into the bloodstream. Which lets the hormones travel to the cells in other parts of the body. This also helps control mood, growth and development, the way our organs work, metabolism and reproduction.
8 0
3 years ago
(06.04 HC)
Ksju [112]

The mass of sodium chloride at the two parts are mathematically given as

  • m=10,688.18g
  • mass of Nacl(m)=39.15g

<h3>What is the mass of sodium chloride that can react with the same volume of fluorine gas at STP?</h3>

Generally, the equation for ideal gas is mathematically given as

PV=nRT

Where the chemical equation is

F2 + 2NaCl → Cl2 + 2NaF

Therefore

1.50x15=m/M *(1.50*0.0821)

1-50 x 15=m/58.5 *(1.50*0.0821)

m=10,688.18g

Part 2

PV=m'/MRT

1*15=m'/58.5*0.0821*273

m'=39.15g

mass of Nacl(m)=m'=39.15g

Read more about Chemical Reaction

brainly.com/question/11231920

#SPJ1

7 0
2 years ago
Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
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