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notka56 [123]
4 years ago
12

Solve the system using substitution. Write the solution as an ordered pair. (1 point) SHOW YOUR WORK FOR FULL CREDIT! (2 points)

Mathematics
2 answers:
Darya [45]4 years ago
7 0

Answer:y = -7, x = 12

Step-by-step explanation:

y + x = 5

x = 5 - y

y = 2(5 - y) + 11

y = 10 - 2y +11

-y -y

0 = 10 - 3y + 11

21 = -3y

y = -7

-7 + x = 5

x = 12

beks73 [17]4 years ago
3 0

x = -2

y = 7

Solution: (-2,7)

//Hope this helps.

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475 boats in 3 hours ratio unit per hour
Dovator [93]
All you have to do is divide 475 by 3 to get the units per hour. When you do that, you get 158.3, and that is your answer. I hope this helps! :)
6 0
3 years ago
Two thirds of a number decreased by six is two. what is the number?
Kisachek [45]
Answer:  The number is:  " 12 ". 

____________________________________
  Let "x" represent "the unknown number" (for which we wish to solve.

The expression:

\frac{2}{3} x  <span>− 6  =  2  ;   Solve for "x" ;  
</span>_______________________________________________
Method 1) 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "\frac{3}{2}" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________
     → \frac{3}{2} * \frac{2}{3} x = 8 * \frac{3}{2} ;

       →  x = 8 * \frac{3}{2} ;

                = \frac{8}{1} * \frac{3}{2} ;

                = \frac{8*3}{1*2} ;
       
                = \frac{24}{2} ;
 
                = <span>1<span>2 .</span></span>
______________________________________________
  x =  12 .
______________________________________________
Method 2)
______________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ; 

   Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:
      →   \frac{2}{3} x = 8 ;
______________________________________________
Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
               → 3 * \frac{2}{3} x = 8 * 3  ;
               → \frac{3}{1} * \frac{2}{3} x = 8 * 3 ;
               → \frac{3*2}{1*3}  x = 8 * 3 
               → \frac{6}{3} x = 24 ; 

                → 2x = 24 ;

 →  Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" : 
 
                    2x / 2 = 24 / 2  ;

                        x = 12 .
__________________________________________________
Method 3).
__________________________________________________
\frac{2}{3} x  − 6  =  2  ;   Solve for "x" ;  
_______________________________________________
Add "6" to EACH SIDE of the equation;
_______________________________________________
       →   \frac{2}{3} x  − 6  + 6 =  2 + 6 ;

to get:

      →   \frac{2}{3} x = 8 ;
______________________________________________
Now, divide each side of the equation by " \frac{2}{3} " ;
  to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________
{\frac{2}{3} x }  /  {\frac{2}{3}}  =  8 / {\frac{2}{3}} ;

to get:  x =  8 / {\frac{2}{3}} ;

                =  8 * (\frac{3}{2} ;

                =  \frac{8}{1}  *  \frac{3}{2} ;

                =  \frac{8*3}{1*2} ;

                =  \frac{24}{2} ;

                = 12 ; 
___________________________________________
                         x = 12 .
___________________________________________
NOTE:  Variant:  (in "Methods 2 & 3") :
___________________________________________
At the point where:
___________________________________________
 =  8 * (\frac{3}{2}) ;

  =  \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
  We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________
  {since: "8÷2 = 4" ; and since:  "2÷2 =1" } ;
__________________________________________
and we can rewrite the expression:
__________________________________________
 \frac{8}{1}  *  \frac{3}{2} ;
__________________________________________
as:   \frac{4}{1}  *  \frac{3}{1} ; 
__________________________________________
which equals:
__________________________________________
→  \frac{4*3}{1*1} ; 

   =   \frac{12}{1} ;

            =  12 .
__________________________________________
         x = 12 . 
__________________________________________
Answer:  The number is:  " 12 ". 
__________________________________________
8 0
4 years ago
12x−5y=−20 y=x+4 x=x=x, equals y=y=y, equals
aksik [14]

Answer:

The solution is (0, 4)

Step-by-step explanation:

Please pay attention to the first two equations and drop the last two:

12x−5y=−20 y=x+4 x=x=x, equals y=y=y   should ideally be:

12x−5y=−20

y=x+4

Let's find x.  Substitute x + 4 for y in the first equation, obtaining:

12x - 5(x + 4) = -20

Carrying out the indicated multiplication, we get:

12x - 5x - 20 = -20, or 7x = 0

If x = 0 then y must be 0 + 4, or 4.  

The solution is (0, 4)

8 0
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Answer:

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