Answer:
You can make Cake CAke Cake Cake and other stuff too Ig
Explanation:
Answer:
6.49g
Explanation:
Let's consider the balanced reaction for photosynthesis.
6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂
We can establish the following relations:
- 1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
- The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
- 1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.
The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:

You just need to multiply the terms and transform to kj by dividing by 1000
1) 10.4kj
2) 14.5 kj
3) 44.8 kj
4) 1.04 kj
and there you go.
Answer:
The mass of the neon gas m = 1.214 kg
Explanation:
Pressure = 3 atm = 304 k pa
Volume = 0.57 L = 0.00057 
Temperature = 75 °c = 348 K
Universal gas constant = 0.0821 
We have to change the unit of this constant. it may be written as
Universal gas constant = 8.314 
Gas constant for neon =
= 0.41 
From ideal gas equation,
P V = m R T ------- (1)
We have all the variables except m. so we have to solve this equation for mass (m).
⇒ 304 ×
× 0.00057 = m × 0.41 × 348
⇒ 173.28 = 142.68 × m
⇒ m = 1.214 kg
This is the mass of the neon gas.
Mass percentage of a solution is the amount of solute present in 100 g of the solution.
Given data:
Mass of solute H2SO4 = 571.3 g
Volume of the solution = 1 lit = 1000 ml
Density of solution = 1.329 g/cm3 = 1.329 g/ml
Calculations:
Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g
Therefore we have:
571.3 g of H2SO4 in 1329 g of the solution
Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987
Mass percentage of H2SO4 (%w/w) is 42.99 %