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ss7ja [257]
3 years ago
13

The term used to describe the Moon phases as the light spreads across the surface of the moon or grows.

Chemistry
1 answer:
katrin [286]3 years ago
5 0

Answer:

Explanation:

New moon

Waxing crescent moon

First quarter moon

Waxing gibbous moon

Full moon

Waning gibbous moon

Last quarter moon

Waning crescent moon

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What is the term for molten material found below the Earths Surface? A lava B Basalt C Magma D Gabbro
guapka [62]
The answer is C, magma. i know lava and magma are the same thing but the correct term is magma. hope this helped, have an amazing day :)
6 0
3 years ago
Read 2 more answers
1
barxatty [35]

Answer:

is 5

Explanation:

Because the baking soda has the same kilograms

4 0
3 years ago
Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

    102.5 = [(\frac{1}{2})x + 498] - [(2)(243)]

    102.5 = (\frac{1}{2})x + 498 - 486

     102.5 - 12 = \frac{x}{2}

           x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

              x = [(\frac{1}{2})181 + (\frac{1}{2})498] - 243

                 = 339.5 - 243

                 = 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
4 Na + O2 2 Na20 grams of Na are required to produce 52.45 grams of Na2O. Round your answer to the nearest whole number​
lukranit [14]

Answer:

4

N

a

+

O

2

→

2

N

a

2

O

.

By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol

N

a

2

O

should result.

Explanation:

The molecular mass of natrium oxide is

61.98

g

⋅

m

o

l

−

1

. If

5

m

o

l

natrium react, then

5

2

m

o

l

×

61.98

g

⋅

m

o

l

−

1

=

154.95

g

natrium oxide should result.

So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go.

Explanation:

5 0
3 years ago
True or False:
Juli2301 [7.4K]

Answer:

Explanation:

From the work of Krogh in 1918 until the present time, a very wide range of values for oxygen diffusion coefficients has been reported1–5 ranging from 1.1 × 10−4 to 4 × 10−8 cm2 sec−1.

7 0
3 years ago
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