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ss7ja [257]
2 years ago
13

The term used to describe the Moon phases as the light spreads across the surface of the moon or grows.

Chemistry
1 answer:
katrin [286]2 years ago
5 0

Answer:

Explanation:

New moon

Waxing crescent moon

First quarter moon

Waxing gibbous moon

Full moon

Waning gibbous moon

Last quarter moon

Waning crescent moon

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The nucleus’ pull on its electrons, taking into account any attractions weakened by shielding is called the:
Sever21 [200]

Answer:

It's called the shielding effect

Explanation:

It describes the decrease in attraction between an electron and the nucleus in any atom with more than one electron shell. (I hope this helps)

8 0
2 years ago
A car traveling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop in 7.5 seconds? What is the cars acc
Marianna [84]

Answer:

The acceleration is: 4m/s^2

Explanation:

Given

u = 30.0m/s --- The initial velocity

t = 7.5s --- time

v = 0m/s -- The final velocity

Required

Determine the acceleration

To do this, we make use of the first equation of motion

v = u - at

We used negative because the car was coming to stop.

This gives:

0 = 30 - 7.5 * a

0 = 30 - 7.5a

Collect like terms

7.5a = 30

Solve for a

a = \frac{30}{7.5}

a = 4m/s^2

6 0
3 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
How many moles are in 7.6 g of Ca
klasskru [66]

Your answer would be 0.024951344877489 but rounding it would be 0.025 moles

7 0
3 years ago
How many formula units are present in 40.0 grams of Cu2S?
11Alexandr11 [23.1K]

Never mind, I did the problem wrong, I deeply apologize.

4 0
2 years ago
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