Answer:
i think number 4 :/ i hope its right...
Answer:
the time at which it passes through the equilibrum position is:
t = 0.1 second
Explanation:
given
w= 4pounds
k(spring constant) = 2lb/ft
g(gravitational constant) = 10m/s² = 32ft/s²
β(initial point above equilibrum) = 1
velocity = 14ft/s
attached is an image showing the calculations, because some of the parameters aren't convenient to type.
Answer:
0.24
Explanation:
Mass of ball= 12g=0.012Kg
height of ball= 2.5m
velocity of ball before falling= 3.2m/s
potential energy of the ball=mgh= 0.012*10*2.5=0.3J
kinetic energy of the ball=0.5*m
=0.5*0.012*3.2*3.2=0.6J
Loss in mechanical energy during the fall= potential energy- Kinetic energy= 0.3-0.06=0.24J
note: During the fall, the potential energy of the ball is converted to kinetic energy. the loss in energy is due to air resistance.
Answer:
Virtual image
Explanation:
Virtual image is formed whenever the rays of an object diverges
Answer:
The frequencies the other string could have are 258.4 Hz and 261.6 Hz.
Explanation:
Given;
beat frequency, Fb = 1.60 Hz
frequency of the first string, F₁ = 260.00 Hz
frequency of the second string, F₂ = ?
Beat frequency is given as;
Fb = F₂ - F₁ or Fb = F₁ - F₂
Fb + F₁ = F₂ or F₂ = F₁ - Fb
1.6 + 260 = F₂ or F₂ = 260 - 1.6
261.6 Hz = F₂ or F₂ = 258.4 Hz
Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.