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Aleksandr [31]
3 years ago
9

An electron has _____

Physics
2 answers:
Soloha48 [4]3 years ago
8 0

Answer:

option (D)

Explanation:

The elementary particles of atom are protons, neutrons and electrons. The protons and neutrons are residing in the nucleus and electron revolves around the nucleus in fixed stationary orbits.

The mass of proton and a neutron is almost same and equal to 1.67 x 10^-27 Kg.

The mass of an electron is 9.1 x 10^-31 Kg.

The mass of electron is much less than the mass of proton or a neutron.

Proton is 1837 times heavier than the electron.

Marrrta [24]3 years ago
3 0

d

a proton and neutron weigh about the same, while an electron is about 1/2000 of the weight of either a proton or neutron

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Answer:

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3 years ago
A mass weighing 4 pounds is attached to a spring whose constant is 2 lb/ft. The medium offers a damping force that numerically e
Neko [114]

Answer:

the time at which it passes through the equilibrum position is:

t = 0.1 second

Explanation:

given

w= 4pounds

k(spring constant) = 2lb/ft

g(gravitational constant) = 10m/s² = 32ft/s²

β(initial point above equilibrum) = 1

velocity = 14ft/s

attached is an image showing the calculations, because some of the parameters aren't convenient to type.

3 0
3 years ago
A 12 g plastic ball is dropped from a height of 2.5 m and is moving at 3.2 m/s just before it hits the floor. How much mechanica
Nataly [62]

Answer:

0.24

Explanation:

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velocity of ball before falling= 3.2m/s

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Loss in mechanical energy during the fall= potential energy- Kinetic energy= 0.3-0.06=0.24J

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4 0
3 years ago
2 Points<br> What type of image is formed by a lens if m= -0.87?
aksik [14]

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4 0
3 years ago
The middle-C hammer of a piano hits two strings, producing beats of 1.60 Hz. One of the strings is turned to 260.00 Hz. What fre
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Answer:

The frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Explanation:

Given;

beat frequency, Fb = 1.60 Hz

frequency of the first string, F₁ = 260.00 Hz

frequency of the second string, F₂ = ?

Beat frequency is given as;

Fb = F₂ - F₁     or      Fb = F₁ - F₂

Fb + F₁ = F₂    or      F₂ = F₁ - Fb

1.6 + 260 = F₂   or   F₂ = 260 - 1.6

261.6 Hz = F₂  or   F₂ = 258.4 Hz

Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.

3 0
3 years ago
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