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brilliants [131]
3 years ago
12

Write multiples and sub-multiples of second​

Physics
2 answers:
aksik [14]3 years ago
7 0
Mark Brainliest please

Multiples / submultiples of time

1 day - 24 hours (h)
1 hour (h) - 60 minute (min)
1 minute (min) - 60 second (s)
1 second (s) - 1000 millisecond (ms)
1 milli second - 1000 microsecond (µs)
gogolik [260]3 years ago
3 0

Explanation:

Submultiples Multiples

Value SI symbol Name

10−1 s ds decasecond

10−2 s cs hectosecond

10−3 s ms kilosecond

I want brainliest plz!!!!!

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Pls help I will give brainlist and don’t give me a link I can’t open them
dezoksy [38]

Answer:

200

Explain:

I have a big brain

5 0
3 years ago
First, you will investigate purely vertical motion. The kinematics equation for vertical motion (ignoring air resistance) is giv
AlladinOne [14]

Answer: It takes 2.85 seconds.

Explanation: according to the question, the kinematics equation for vertical motion is

y(t) = y_{0} + v_{0} .t - \frac{1}{2} .gt^{2}

y₀ is the initial postion and equals 0 because it is fired at ground level;

v₀ is the initial speed and eqauls 14m/s;

g is gravity and it is 9.8m/s²;

y(t) is the final position and equals 0 because it is when the pumpkin hits the ground;

Rewriting the equation, we have:

0 + 14t - \frac{1}{2}.9.8.t^{2} = 0

14t - 4.9t² = 0

t(14 - 4.9t) = 0

For this equation to be zero,

t = 0 or

14 - 4.9t = 0

- 4.9t = - 14

t = \frac{14}{4.9}

t = 2.86

It takes 2.86 seconds for the pumpkin to hit the ground.

6 0
3 years ago
What does an unconformity in a sequence of rock layers reveal about geologic history?
dedylja [7]
Your answer will be “ b “
8 0
3 years ago
Read 2 more answers
An unknown source plays a pitch of middle C (262 Hz). How fast would the sound wave from this source have to travel to raise
Viefleur [7K]

Answer:

The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

Option: c

Explanation:

Unknown source plays of middle C (fs) = 262 Hz

The sound wave from this source have to travel to raise the pitch to C sharp is (fd) = 272 Hz

\begin{array}{l}{velocity of sound in air(v)=343 \mathrm{m} / \mathrm{s}, f_{\mathrm{s}}=262 \mathrm{Hz}, f_{\mathrm{d}}=271 \mathrm{Hz}} \\ {velocity of receiver(v_{\mathrm{d}})=0 \mathrm{m} / \mathrm{s},velocity of source( v_{\mathrm{s}}) \text { is unknown }}\end{array}

\text { Speed of sound } \mathrm{V}_{\mathrm{S}}=343 \mathrm{m} / \mathrm{s}

f_{\mathrm{d}}=f_{\mathrm{s}}\left(\frac{v-v_{\mathrm{d}}}{v-v_{\mathrm{s}}}\right)

\frac{f_{d}}{f_{s}}=\left(\frac{v-v_{d}}{v-v_{s}}\right)

\left(v-v_{s}\right)=\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

v_{s}=v-\frac{f_{s}}{f_{d}}\left(v-v_{d}\right)

Substitute the given values in the formula,

v_{s}=343+\frac{262}{271}(343-0)

v_{s}=343+0.966(343)

v_{s}=343-331.33

v_{s}=11.4 \mathrm{m} / \mathrm{s}

Therefore, The sound travels at v_{s}=11.4 \mathrm{m} / \mathrm{s}

4 0
3 years ago
A rock is dropped from the top of a tower. When it is 40 meters above the ground velocity of 17 m/s. When its velocity is 24 m/s
eimsori [14]

Answer:

Option B is the correct answer.

Explanation:

Let us consider 40 meter above ground as origin.

Initial velocity = 17 m/s

Final velocity = 24 m/s

Acceleration = 9.81 m/s

We have equation of motion v² = u² + 2as

Substituting

         24² = 17² + 2 x 9.81 x s

           s = 14.63 m

Distance traveled by rock = 14.63 m down.

Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m

Option B is the correct answer.

4 0
4 years ago
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