The cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
<h3>
Acceleration of the cart</h3>
The acceleration of the cart is determined from the net force acting on the mass-cart system.
Upward force = Downward force
ma = mg
13a = 10(9.8)
13a = 98
a = 98/13
a = 7.54 m/s²
Thus, the cart's acceleration to the right after the mass is released is determined as 7.54 m/s².
Learn more about acceleration here: brainly.com/question/14344386
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Actually what the problem meant about the westward
component of the ball’s displacement is the horizontal component of the
displacement. To help us better understand the problem, I attached a figure of
the situation.
We can see from the figure that to solve for the value of
the horizontal component, we have to make use of the sin function. That is:
sin θ = side opposite to the angle / hypotenuse of the
triangle
sin 42 = x / 40 m
x = (40 m) sin 42
x = 26.77 m
Therefore the ball has a westward
displacement of about 26.77 m
Answer:
4.3 * 10^28 kg
Explanation:
Given:
Period, T = 84s
Radius of satellite orbit, r = 8*10^6
Using the relation :
M = 4π²r³ / GT²
Where G = Gravitational constant, 6.67 * 10^-11
M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2
M = (20218.191872 * 10^18) / 47063.52 * 10^-11
M = 0.4295937 * 10^18 - (-11)
M = 0.4295937 * 10^29
M = 4.295937 * 10^28 kg
M = 4.3 * 10^28 kg
Mass of planet Nutron = 4.3 * 10^28 kg
