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Katen [24]
3 years ago
14

Proper design of automobile braking systems must account for heat buildup under heavy braking. Part A Calculate the thermal ener

gy dissipated from brakes in a 1600 kg car that descends a 15 ∘ hill. The car begins braking when its speed is 95 km/h and slows to a speed of 40 km/h in a distance of 0.34 km measured along the road.
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

1838216 J

Explanation:

95 km/h = 26.39 m/s

40 km/h = 11.11 m/s

Initial kinetic energy

= .5 x 1600 x(26.39)²

= 557145.67 J

Final kinetic energy

= .5 x 1600 x ( 11.11)²

= 98745.68 J

Loss of kinetic energy

= 458400 J

Loss of potential energy

= mg x loss of height

= 1600 x 9.8 x 340 sin 15

= 1379816 J

Sum of Loss of potential energy and Loss of kinetic energy

=  1379816 + 458400

= 1838216 J

This is the work done by the friction . So this is heat generated.

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10. The shape of the earth is<br> A taco<br> b. A carrot<br> C. A sphere<br> d. A potato
expeople1 [14]

Answer:

C. A sphere.

Explanation:

I'm 100% sure.

6 0
3 years ago
Which is the correctly balanced equation for the reaction of rust, Fe2O3, and hydrochloric acid, HCl?
Mariana [72]

Answer: Option (c) is correct answer.

Explanation:

The given reaction equation is as follows.

          Fe_{2}O_{3} + HCl \rightarrow FeCl_{3} + H_{2}O

The number of atoms on reactant side are as follows.

  • Fe = 2
  • O = 3
  • H = 1
  • Cl = 1

The number of atoms on product side are as follows.

  • Fe = 1
  • O = 1
  • H = 2
  • Cl = 3

Therefore, in order to balance the equation we will balance the number of atoms in both reactant and product side.

Since number of Fe atoms in reactant side is 2, therefore, multiply FeCl_{3} by 2 in the product side.

Number of O atoms in reactant side is 3, therefore, multiply H_{2}O by 3 in the product side.

Now, the number of H atoms on product side is 6, therefore, multiply HCl by 6 in the reactant side.

The number of chlorine atoms on both reactant and product side equals 6.

Thus, the equation will become as follows.

             Fe_{2}O_{3} + 6HCl \rightarrow 2FeCl_{3} + 3H_{2}O

Hence, the equation is balanced.

5 0
4 years ago
Read 2 more answers
Which of these statements is most likely correct about the Nebular theory of formation of planets?
exis [7]
Correct answer is D.

Explanation:
A) is not correct answer because this type of theory can not become law. Laws are properties that are same in any part of universe. Nebular theory is not correct for every part of universe.

B) is not correct answer because this theory could be replaced if some evidence show that some other theory is more likely to be correct.

C) is not correct answer because the study has been done on other nebulas in our galaxy. There are many nebulas and by obserwing them this theory was developed.
4 0
4 years ago
Explain the correspondence that lets us easily translate between linear motion and rotational motion. What are the linear analog
RideAnS [48]

Explanation:

The linear analog of angle is angle itself.

The linear analog of angular velocity is linear velocity.

ω is angular velocity, therefore linear velocity is given by v

∴ for linear velocity, v^{2} = u^{2}+2.a.S

   for angular velocity, \omega_{f}^{2}  = \omega _{i}^{2}+2.a.S

The linear analog of angular acceleration is acceleration.

α is angular acceleration whereas as a is linear acceleration.

∴ for linear acceleration, v = u + a.t

  for angular acceleration, \omega_{f}= \omega _{i}+\alpha .t

The linear analog of moment of inertia is mass.

I is moment of inertia and m is mass,

∴ for linear analog, F = m.a

  for angular analog, τ - I.α

4 0
3 years ago
The distance between the centers of the wheels of a motorcycle is 146 cm. The center of mass ofthe motorcycle, including the rid
Vitek1552 [10]

Answer:

9.12267515924 m/s²

Explanation:

Here the moment created by the wheels and the moment created by the center of gravity will balance each other.

h = Height of the center of mass = 78.5 cm

d =  Distance from back wheel to the center of mass = \dfrac{146\times 10^{-2}}{2}\ m

g = Acceleration due to gravity = 9.81 m/s²

a = Horizontal acceleration

The equation is of the form

mgd=Fh\\\Rightarrow mgd=mah\\\Rightarrow a=\dfrac{gd}{h}\\\Rightarrow a=\dfrac{9.81\times \dfrac{146\times 10^{-2}}{2}}{78.5\times 10^{-2}}\\\Rightarrow a=9.12267515924\ m/s^2

The horizontal acceleration of the motorcycle that will make the front wheel rise off the ground is 9.12267515924 m/s²

8 0
3 years ago
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