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Katen [24]
3 years ago
14

Proper design of automobile braking systems must account for heat buildup under heavy braking. Part A Calculate the thermal ener

gy dissipated from brakes in a 1600 kg car that descends a 15 ∘ hill. The car begins braking when its speed is 95 km/h and slows to a speed of 40 km/h in a distance of 0.34 km measured along the road.
Physics
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

1838216 J

Explanation:

95 km/h = 26.39 m/s

40 km/h = 11.11 m/s

Initial kinetic energy

= .5 x 1600 x(26.39)²

= 557145.67 J

Final kinetic energy

= .5 x 1600 x ( 11.11)²

= 98745.68 J

Loss of kinetic energy

= 458400 J

Loss of potential energy

= mg x loss of height

= 1600 x 9.8 x 340 sin 15

= 1379816 J

Sum of Loss of potential energy and Loss of kinetic energy

=  1379816 + 458400

= 1838216 J

This is the work done by the friction . So this is heat generated.

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Why the rusting of iron is slow in the deserts than in the coastal areas?​
gulaghasi [49]

Answer:

Rusting of iron is slow in desert area because rusting happens when iron articles react with atmospheric oxygen and moisture and produced a substance called rust. in desert areas there is less moisture in air as compared to coastal area therefore rusting is slow.

6 0
3 years ago
In which number are the zeros not significant?<br> 100.0<br> O 0.0003<br> O 4.00005<br> O 1.0004
tensa zangetsu [6.8K]

Answer:

0.0003

Explanation:

In the rules of Sig Figs, all zeros before with decimals are not sigificant. I.E. 0.00000000000000009. Despite how many 0's there are, only the 9 is significant. Zeros before a number is not significant. In 100, only the one is signficant in 100. with a dot at the end, the one and the two zeros are significant. hope this helps.

7 0
3 years ago
Read 2 more answers
The diagram shows two charged objects, X and Y.
Vanyuwa [196]

D:

X: positive

Y: positive

Explanation:

To answer correctly the question, we need to remind the difference between the electric field produced by a positive charge and by a negative charge:

- For a positive charge, the direction of the field lines is away from the charge (because they represent the direction in which a positive test charge would move, if placed in this field)

- For a negative charge, the direction of the field lines is toward the charge (because the positive test charge would move toward the negative charge, if placed in this field)

In the figure, we see that both charges have electric field lines that go away from the charges: therefore, according to the previous statements, they both have to be positive charges.

7 0
3 years ago
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An object initially traveling at a velocity of 52 m/s experiences an acceleration of 9.8 m/s^2 how much time will it take to com
Goshia [24]

Answer:

5.3 seconds

Explanation:

Vx = Vx0 + Ax .T

A= de-acceleration

Vx =0   final at rest velocity

Vx0 = initial velocity

T= time to bring the object to a stop

therefore

0 = 52 m/s - (9.8 m/s^2) . T

-52 m/s/ -9.8 m/sec^2 =T

5.3 seconds= T

8 0
3 years ago
A particle of massmand chargeqenters a region of uniform magneticfieldB=B0ˆz. The field region extends fromx= 0 tox=L, and is ef
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Answer: positive

Explanation:idk

7 0
3 years ago
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