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Ray Of Light [21]
3 years ago
6

The actual width of a store room is 280 centimetre.if the scale chosen to make its drawing is 1:7,then the width of the room in

the drawing will be 40 cm
Plz plz plz answer my question I have asked 1 more and I haven't gotten the ans yet
If a length of 100 m is represented on a map by 1 cm,then The actual distance corresponding to 2 cm is 200 m

Plz plz plz help me friends plz...
Mathematics
1 answer:
Elden [556K]3 years ago
8 0

Answer:

dude youve got no question...

Step-by-step explanation:

if the actual width is 280 and your map shows 40cm, the scale is 1:7, with respect to the map

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NEED HELP ASAP What is the perimeter of the triangle
marin [14]

Answer:

its a right angle and a its an acute angle as well so it be 5

8 0
3 years ago
Need help with this function problem
kotykmax [81]

Answer:

  see attached

Step-by-step explanation:

To find the inverse function, solve ...

  x = f(y)

  x = (y^7)/7 -4 . . . . . . . use the definition of f(x)

  x +4 = (y^7)/7 . . . . . . add 4

  7(x +4) = y^7 . . . . . . multiply by 7

  (7(x +4))^(1/7) = y . . take the 7th root

The inverse function is the one shown in the attachment.

4 0
2 years ago
Alex is trying to run a certain number of miles by the end of the month Alex is 40% of the way to achieving her goal and she alr
docker41 [41]

Answer:

30 miles

Step-by-step explanation:

Given that:

Alex has some target to run a certain number of miles by the end of the month.

Goal already achieved = 40% of the total goal

Number of miles already run by Alex = 12 miles

To find:

Number of miles that Alex is trying to run by the end of month?

Solution:

We have to find nothing but the goal of Alex here.

Let the number of miles that Alex is trying to run by the end of the month = x miles

As per question statement:

40% of total number of miles to be run = 12 miles

OR

\dfrac{40}{100}\times x = 12\\\Rightarrow 40x=12\times 100\\\Rightarrow x = \dfrac{1200}{40}\\\Rightarrow \bold{x = 30\ miles}

Total number of miles that Alex is trying to run by the end of the month = <em>30 miles</em>

4 0
3 years ago
How do I solve this?
andreev551 [17]

Answer:

x is in the range [-1,4]

Step-by-step explanation:

I haven't worked with absolute value inequalities in awhile, but let's take a wack at this.

We are given the following inequality:

| 2x - 3 | <= 5

This implies two possible cases:

[1] -5 <= 2x -3

Or

[2] 2x - 3 <= 5

So let's solve x for both of these cases:

[1] -5 <= 2x - 3

 -2 <= 2x

 -1  <= x

[2]  2x - 3 <= 5

 2x <= 8

  x <= 4

So from these cases, we can say the following is true:

x >= -1  and x <= 4

Thus, we can write this in the form

-1 <= x <= 4

Or in interval notation:

{ x is element of reals | -1 <= x <= 4}

Also written as

x is in the range [-1,4]

Where the closed brackets represent 1 and 4 as possible answers whereas parenthesis would imply they were not.

Cheers.

4 0
3 years ago
A business owner collected data on the people working for her company. She determined the average number of minutes each employe
Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.<em> </em>

Step-by-step explanation:

The following information is missing

<em>A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.  </em>

<em>A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.  </em>

<em>The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison? </em>

<em>The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric. </em>

<em>The comparison would be more accurate using the mean and MAD because the median of both data sets is the same. </em>

<em>The comparison using median and IQR is best because one of the graphs is not symmetrical. </em>

<em>The comparison using median and IQR is best because the median is greater than the IQR for both data sets.</em>

<em />

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0
4 years ago
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