2 years ago

What are the energy transfers in a torch?

1 answer:

6 0

Explanation:

The battery is a store of internal energy (shown as chemical energy). The energy is transferred through the wires to the lamp, which then transfers the energy to the surroundings as light. These are the useful energy transfers - we use electric lamps to light up our rooms.

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You buy a plastic dart gun, and being a clever physics student you decide to do a quick calculation to find its maximum horizont

Scilla [17]

Answer:

$R_{max} = 51.84 m$

Explanation:

When we shoot the dart upwards the time taken by the dart to go straight up and again come back is given as

$t = 4.6 s$

here we can say

$\Delta y = 0 = v_i t + \frac{1}{2}at^2$

$0 = v_i t - \frac{1}{2}(9.8)t^2$

put t = 4.6 s then we have

$v_i = 22.54 s$

Now in order to find the maximum range we can say

$R = \frac{v^2 sin2\theta}{g}$

so in order to have maximum range we can say

$\theta = 45 degree$

$R_{max} = \frac{v^2}{g}$

$R_{max} = \frac{22.54^2}{9.8}$

$R_{max} = 51.84 m$

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2 years ago

When a cannon fires a cannonball, the cannon will recoil backward because the?

ludmilkaskok [199]

For every action there is an equal and opposite reaction. Newton's Third Law of Motion.

4 0

2 years ago

Two balls are placed near one another and hang down, as shown below.

Delicious77 [7]

Answer:

<h2>a- neither ball has a charge</h2>

Explanation:

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2 years ago

Read 2 more answers

A basketball player standing under the hoop launches the ball straight up with an initial velocity of v₀ = 3.25 m/s from 2.5 m a

matrenka [14]

Answer: 0.53m

Explanation:

According to the equation of motion v²= v₀²+2as

Since the body is launched upward, the final velocity at the maximum height will be "zero" since the body will momentarily be at rest at the maximum height i.e v = 0

Initial velocity given (v₀) = 3.25 m/s

The body is also under the influence of gravity but the acceleration due to gravity will be negative being an upward force (a = -g) and the distance (s) will serve as our maximum height (h)

The equation of motion will.now become

V = v₀² -2gh

Where v = 0 v₀ = 3.25m/s g = 10m/s h = ?

0 = 3.25² - 2(10)h

0 = 10.56 - 20h

-10.56 = -20h

h = 10.56/20

h = 0.53m

Therefore, the maximum height, h (in meters), above the launch point that the basketball will achieve is 0.53m

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3 years ago

What is the closest city near Susquehanna river?

Roman55 [17]

City of Pittston City Hall

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2 years ago