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3 years ago

7

What is the major factor controlling how levers work?

1 answer:

Gekata [30.6K]3 years ago

7 0

Answer:

Displacement between Fulcrum, Job and Force

Explanation:

The employment and use of levers is simple. Levers reduce the force required to do a task by introducing the concept of moment.

There are there components in a simple lever.

1) The Fulcrum

2) The Job (Load)

3) The Force (Effort)

Typically if it weren't for levers then the three points/components would be at the same point. A lever creates a displacement between all these three components create moment. The higher the displacement between the three the lower the force (effort) required to do the job (lift the load).

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Find a glass jar with a screw-top metal lid. Close the lid snugly and put the jar into the refrigerator. Leave it there for abou

DochEvi [55]

Answer:

The lid becomes tighter

It becomes tighter because metals have a lower heat capacity than glass meaning their temperature drops (or increases) much faster than glass for the same energy change. So in this example, the metal will contract faster than the glass causing it to be more tighter around the glass.

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4 years ago

A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even thoug

vlada-n [284]

Answer:

The Minimum wavelength is $\lambda_{min}= 382.2nm$

The Maximum wavelength is $\lambda_{max}= 624.2nm$

Explanation:

From the question we are told that

The energy range is $E_r = 3.25eV \ and \ 19.9eV$

Considering $E = 19.9eV$

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

$E = 19.9eV = 19.9 *1.6 *10^{-19}J$

This energy is mathematically represented as

$E = \frac{hc}{\lambda_{max}}$

Here h is the Planck's constant with value of $h= 6.625*10^{-34}J\cdot s$

c is the speed of light with value of $c = 3*10^8 m/s$

Substituting values and making $\lambda$ the subject of the formula

$\lambda_{max} = \frac{hc}{E}$

$= \frac{6.625*10^{-34} * 3.0*10^{8}}{19.9*1.6*10^{-19}}$

$\lambda_{max}= 624.2nm$

Considering $E = 3.25eV$

When a single photon is transferred to to an electron the energy obtained can be calculated as follows

$E = 19.9eV = 3.25 *1.6 *10^{-19}J$

This energy is mathematically represented as

$E = \frac{hc}{\lambda_{min}}$

Substituting values and making $\lambda$ the subject of the formula

$\lambda_{min} = \frac{hc}{E}$

$= \frac{6.625*10^{-34} * 3.0*10^{8}}{3.25*1.6*10^{-19}}$

$\lambda_{min}= 382.2nm$

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3 years ago

Two plane mirrors stand facing each other, 3.08 m apart, and a woman stands between them. The woman faces one of the mirrors fro

Svetllana [295]

Answer:

A) 1.3m

B) it shows the back of her hand

C) 4.86m

D) it shows the palm of her hand

E) 7.46m

F) it shows the back of her hand.

Explanation:

Detailed explanation is shown in the illustrative diagram below.

6 0

3 years ago

Read 2 more answers

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defon

Answer:562800

Explanation:

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2 years ago

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