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ioda
3 years ago
5

Which is an example of an abiotic factor in a pond environment?

Physics
2 answers:
Allushta [10]3 years ago
7 0
The water <span>is an example of an abiotic factor in a pond environment</span>
vesna_86 [32]3 years ago
3 0
"Non-Living" things are known as "Abiotic factor" in the ecosystem.

In short, Your Answer would be: Option A) The Water

Hope this helps!
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What is the momentum of and 200 kg car traveling south at 22 m/sec?
motikmotik
The momentum of the car is 4.4x10^3 kg•m/sec
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2 years ago
A long uniform board weighs 52.8 N (10.6 lbs) rests on a support at its mid point. Two children weighing 206.0 N (41.2 lbs) and
natima [27]

The upward force exerted on the board by the support is 530.8 N.

<h3>Upward force exerted on the board by the support</h3>

The sum of the upward forces is equal to sum of downward forces;

total downward forces = 52.8 N + 206 N + 272 N = 530.8 N

downward force = upward force = 530.8 N

Thus, the upward force exerted on the board by the support is 530.8 N.

Learn more about upward force here: brainly.com/question/6080367

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1 year ago
Can a solution be separated by filtration?​
alexgriva [62]

Answer:

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Explanation:

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8 0
3 years ago
Read 2 more answers
A constant-volume perfect gas thermometer indicates a pressure of 6.69 kPa at the triple point temperature of water (273.16 K).
mina [271]

Answer:

(a) ΔP=0.0245 kPa

(b) P=9.14 kPa

(c)ΔP=0.0245 kPa

Explanation:

(a) As it is perfect gas we can use

(P₁V₁)/T₁=(P₂V₂)/T₂

Since this constant volume so

P₁/T₁=P₂/T₂

T₂ is change in temperature

T₂=1.00+273.16

T₂=274.16 K

P_{2}=(\frac{6.69}{273.16} )*274.16\\P_{2}=6.71449 kPa

ΔP=6.71449-6.69

ΔP=0.0245 kPa

(b) As

P_{2}=(\frac{6.69}{273.16} )*373.16\\P_{2}=9.14 kPa

(c) Same steps as in part (a)

P_{2}=(\frac{9.14}{373.16} )*374.16\\P_{2}=9.164kPa

ΔP=9.164-9.14

ΔP=0.0245kPa

8 0
3 years ago
Select the correct answer.
kherson [118]

Answer:

B chemical energy

Explanation:

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2 years ago
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