Car A take a time of 2.55hr and car B take a time of 2.14 hr
We know that distance divide by time is speed
here it is given that car A to reach a gas station a distance 189 km from the school traveling at a speed of 74 km/hr
so speed=distance/time
s=d/t
t=d/s
=189/74
=2.55hr
In case of car B it is given that The distance from the is 199.8km, car b is traveling at a speed of 93 km/hr
s=d/t
t=d/s
=199.8/93
=2.14hr
so from the above given data and the formula we solved and found out the time taken by car A is 2.55h and car B is 2.14h
learn more about Speed here brainly.com/question/13943409
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Answer:
v = 0.489 m/s
Explanation:
It is given that,
Mass of a box, m = 1.5 kg
The compression in the spring, x = 6.5 cm = 0.065 m
Let the spring constant of the spring is 85 N/m
We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.


So, the speed of the box is 0.489 m/s.
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First of all, that equation is not correct, which may be the reason
that you're having trouble assigning units to the quantities.
Power is defined as [energy / time], so [Energy] = [ power x time ],
and
[Time] = [ energy / power ].
Unit-wise, these equations are correct just as they appear here,
with no proportionality constants or conversion factors, when ...
[ Power ] = watts
[ Energy ] = joules
[ Time ] = seconds .
There is no difference. 5 is the same as 5.0