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Vera_Pavlovna [14]
3 years ago
15

Find the force necessary to start the crate moving, given that the mass of the crate is 32 kg and the coefficient of static fric

tion between the crate and the floor is 0.58.
Physics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

181.89 N

Explanation:

The force necessary to start the create moving = frictional force.

F = μR................... Equation 1

Where F = Force necessary to start the create moving, μ = coefficient of static friction. R = normal reaction.

But,

R = mg ........................ Equation 2

Where m = mass of the crate, g = acceleration due to gravity of the plate.

Substitute equation 2 into equation 1

F = μmg...................... Equation 3

Given: m = 32 kg, μ = 0.58, g = 9.8 m/s²

Substitute into equation 3

F = 32(9.8)(0.58)

F = 181.89 N

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Answer:

It reveals that light is a wave

Explanation:

Diffraction is the property of a wave in which there is a bending of the wave about the corners of an obstacle or aperture into the geometrical shadow of the obstacle or aperture.

This simply implies that a wave bends or spreads out when it passes through openings. Since the light diffracts through small slits and diffraction has been shown to occur in water waves and sound waves, this property of diffraction can only be characteristic of a wave and thus, this evidence reveals that light is a wave.

3 0
3 years ago
How much work is done by the force of gravity when the book is released?
Naya [18.7K]

Answer:

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Explanation:

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3 0
3 years ago
Water boiling<br><br> Which one is shown? (Look at pic)
Mkey [24]

Answer:

conduction.

Explanation:

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4 0
3 years ago
A pitcher throws a 0.144-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just
Solnce55 [7]

(a) 12.8 kg m/s

The impulse delivered by the bat on the baseball is equal to the change in momentum of the baseball:

I=\Delta p = m(v-u)

where we have

m = 0.144 kg is the mass of the ball

v = -47 m/s is the final velocity of the ball

u = 42 m/s is the initial velocity of the ball

Substituting into the equation, we find

I=(0.144 kg)(-47 m/s-(42 m/s))=-12.8 kg m/s

And since we are interested in the magnitude only,

I=12.8 kg m/s

(b) 2.78 kN

The impulse exerted on the ball is also equal to the product between the average force and the contact time:

I=F\Delta t

where

F is the average force exerted on the ball

\Delta t=0.0046 s is the contact time

Solving the formula for F, we find

F=\frac{I}{\Delta t}=\frac{12.8 kg m/s}{0.0046 s}=2783 N = 2.78 kN

(c) The force exerted on the ball is much larger (1988 times more) than the weigth of the ball

The weight of the ball is given by

W=mg

where

m = 0.144 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the equation for W, we find

W=(0.144 kg)(9.8 m/s^2)=1.4 N

So as we see, the force exerted on the ball (2783 N) is almost 2000 times larger than the weight of the ball (1.4 N):

\frac{F}{W}=\frac{2783 N}{1.4 N}=1988

8 0
3 years ago
3) What is the weight of an object with a mass of 5.2 kilograms?​
inna [77]

Answer:

50.96 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.

w = m x g

w = 5.2 kg x 9.8 m/s^2

w = 50.96 N

The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!

8 0
3 years ago
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