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SVEN [57.7K]
2 years ago
8

If pizza is round will it roll off a cliff?

Physics
1 answer:
Rina8888 [55]2 years ago
6 0
If a pizza is round like a ball it will roll off a cliff.If it’s just flat and round it won’t.
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A ball with mass M, moving horizontally at 4.00 m&gt;s, collides elastically with a block with mass 3M that is initially hanging
Ivan

Answer:

θ = 53.7°

Explanation:

Given:

- The mass of ball = M

- The mass of object = 3M

- The wire length L = 0.5 m

- The velocity of ball vi = 4.0 m/s

- The velocity of ball vf

- The velocity of object Vf

Find:

Find the maximum angle through which the block swings after it is hit.

Solution:

- When two objects collide with no external force acting on the system the linear momentum of the system is conserved. The initial (Pi) and final (Pf) linear momentum are equal:

                                  Pi = Pf

                                  M*vi = M*vf + 3M*Vf

                                  vi = vf + 3*Vf

                                  4 = vf + 3*Vf

- For elastic collision between two particles the relative velocities before and after collision have the same magnitude but opposite sign; so,

                                   vi - 0 = Vf - vf

                                   4 = Vf - vf

- Solve the above two equation simultaneously.

                                   8 = 4*Vf

                                   Vf = 2 m/s

                                    vf = -2 m/s

- When the ball hits the object it swing under the influence of gravity only. Hence, no external force acts on the object so we can apply the conservation of energy as the object attains a height h.

                                   ΔK.E = ΔP.E

                                   0.5*(3M)*Vf^2 = (3M)*(g)*(h)

                                   h = Vf^2 / 2*g

- Plug in the values:

                                   h = 2^2 / 2*9.81

                                   h = 0.2039 m

- We can see that the maximum angle can be given as θ according trigonometric relation as follows:

                                  θ = arccos [ ( L - h ) / L ]

                                  θ = arccos [ ( 0.5 - 0.2039 ) / 0.5 ]

                                  θ = 53.7°

6 0
2 years ago
A car traveling 28 mi/h accelerates uniformly for 8.9 s, covering 599 ft in this time. what was its acceleration? round your ans
almond37 [142]

Answer:

5.90 ft/s^2

Explanation:

There are mixed units in this question....convert everything to miles or feet

    and hr  to s

28 mi / hr = 41.066 ft/s

Displacement = vo t + 1/2 at^2

         599       =  41.066 (8.9)  + 1/2 a (8.9^2)

                      solve for a = ~ 5.90 ft/s^2

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