The final pressure of the gas in the container is 4 atm
From the question given above, the following data were obtained:
Initial volume (V₁) = 4 L
Initial temperature (T₁) = 300 K
Initial pressure (P₁) = 1 atm
Final temperature (T₂) = 600 K
Final volume (V₂) = 2 L
<h3>Final pressure (P₂) =?</h3>
- Using the combine gas equation, we can obtain the final pressure of the gas as illustrated below:
Cross multiply
300 × 2 × P₂ = 4 × 600
600 × P₂ = 2400
Divide both side by 600
<h3>P₂ = 4 atm</h3>
Therefore, the final pressure of gas is 4 atm.
Learn more: brainly.com/question/23558057
Answer:
0,040 M
Explanation:
The global reaction of the problem is:
Al(OH) (s) + OH⁻ ⇄ Al(OH)₂⁻(aq) K= 40
The equation of equilibrium is:
K = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)][OH^-]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%5BOH%5E-%5D%7D)
The concentration of OH⁻ is:
pOH = 14 - pH = <em>3</em>
pOH = -log [OH⁻]
[OH⁻] = 1x10⁻³
Thus:
40 = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)][1x10^{-3}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%5B1x10%5E%7B-3%7D%5D%7D)
<em>0,04M = ![\frac{[Al(OH)_{2} ^-]}{[Al(OH)]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAl%28OH%29_%7B2%7D%20%5E-%5D%7D%7B%5BAl%28OH%29%5D%7D)
</em>
This means that 0,04 M are the number of moles that the solvent can dissolve in 1L, in other words, solubility.
I hope it helps!
Answer:
The biochemical properties of water are 1) chemical structure of water 2) water is a good solvent 3) hydrogen bonding. 4) sticky, wet water 5)the density of ice and water
Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams
So you would need 1.2kg or 1200 grams to make a 40% solution
I positive that the answer is wolf hope that helps
