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galben [10]
4 years ago
13

Two asteroids in outer space collide, and stick together. The mass of each asteroid, and the velocity of each asteroid before th

e impact, are known. To find the momentum of the stuck-together asteroids after the impact, what approach would be useful? Use the momentum principle. Use the relationship between velocity, displacement, and time. It depends on whether the collision was elastic or inelastic. Use the energy principle. It depends on whether or not the speed of the asteroids was near the speed of light. Additional Materials
Physics
1 answer:
zepelin [54]4 years ago
8 0

Answer:

Use the momentum principle

Explanation:

If two asteroids in outer space collide, and stick together and the mass of each asteroid, and the velocity of each asteroid before the impact, are known then the approach that will be useful in analysing this collision is using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of momentum of the bodies after collision. The bodies moves with the same velocity after collision

Let m1 and m2 be the masses of the asteroid

u1 and u2 be their velocity before collision

v be their common velocity

Since momentum = mass × velocity

The relationship that can be used to analyse the approach is;

m1u1 + m2u2 = (m1+m2)v

Note that even though the collision is elastic, the law of conservation will still be used. As a matter of fact this approach can be used if the collision is either elastic or inelastic.

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xxTIMURxx [149]
D Is Thw Correct answer
3 0
4 years ago
A 45 kg object has a momentum of 225 kg-m/s northward. What is the object's velocity?
melomori [17]

Answer: 5 m/s North

Explanation:

Velocity = Momentum/Mass

Velocity = 225 kg*m/s/45kg

Velocity = 5 m/s North

3 0
2 years ago
If the speed of an object increases, the kinetic energy will ______________ because _____________________________________.
Svetlanka [38]
Increase because kinetic energy is all about the speed of an object and the more speed the more kinetic energy.
5 0
3 years ago
A magnetic field is entering into a coil of wire with radius of 2(mm) and 200 turns. The direction of magnetic field makes an an
frozen [14]

Answer:

a) <em>2.278 x 10^-5 volts</em>

b) <em>1.139 x 10^-6 Ampere</em>

c) <em>2.59 x 10^-11 W</em>

Explanation:

The radius of the wire r = 2 mm = 0.002 m

the number of turns N = 200 turns

direction of the magnetic field ∅ = 25°

magnetic field strength B = 0.02 T

varying time = 2 sec

The cross sectional area of the wire = \pi r^{2}

==> A = 3.142 x 0.002^{2} = 1.257 x 10^-5 m^2

Field flux Φ = BA cos ∅ = 0.02 x 1.257 x 10^-5 x cos 25°

==> Φ = 2.278 x 10^-7 Wb

The induced EMF is given as

E = NdΦ/dt

where dΦ/dt = (2.278 x 10^-7)/2 = 1.139 x 10^-7

E = 200 x 1.139 x 10^-7 = <em>2.278 x 10^-5 volts</em>

<em></em>

<em></em>

b) If the two ends are connected to a resistor of 20 Ω, the current through the resistor is given as

I = E/R

where R is the resistor

I = (2.278 x 10^-5)/20 = <em>1.139 x 10^-6 Ampere</em>

<em></em>

<em></em>

<em> </em>c) power delivered to the resistor is given as

P = IE

P = (1.139 x 10^-6) x (2.278 x 10^-5) = <em>2.59 x 10^-11 W</em>

4 0
3 years ago
The velocity versus time graph of particle A is tangent to the velocity versus time graph for particle B at point O. What is the
lara [203]
As velocities are tangent, the value of both Particle A and Particle B would be same for that point O (Intersecting point)

a = v / t
Here, v = 7, t = 6
So, a = 7/6
a = 1.17 
As the graph is decreasing, value of acceleration would be negative.
So, a = -1.17 m/s²

In short, Your Answer would be Option C

Hope this helps!
7 0
3 years ago
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