Answer:
82780.42123 m/s
14.45 days
Explanation:
m = Mass of the planet
M = Mass of the star = 
r = Radius of orbit of planet = 
v = Orbital speed
The kinetic and potential energy balance is given by

The orbital speed of the star is 82780.42123 m/s
The orbital period is given by
The orbital period is 14.45 days
Answer:
-19.9m/s²
Explanation:
Given that
vi = 14cm/s
xi = 2.94 cm
xf=-5.00 cm
t= 1.85s
So
Using xf-xi= vi t + 1/2at²
Which is = -5-2.94= 14*1.85+1/2a1.85²
= -7.94= 25.9+1.7a
-33.9= 1.7a
a= - 19.9m/s²
Answer:
19.822 kPa
Explanation:
= Density of blood = 1060 kg/m³
g = Acceleration due to gravity = 10 m/s²
h = Height of person = 187 cm
The pressure difference would be given by the relation (as there are no other forces to be considered)

The difference in blood pressure is 19.822 kPa
Answer:
Explanation:
Let T be the tension in the string and mg is the weight of the block.
T = mg
By using Newton's second law
T - mg = ma
mg - mg = ma
a = 0
Thus, the acceleration is zero.
Describing motion from each frame of reference:
Since observer A is on one of the train's cars, he will find that he is at rest with respect to the train even when it is pulling away because, he is also moving with respect to the train.
Observer B on the stationary platform will observe that the train is pulling away from the station towards the right of the platform. as is described
Observer C will notice that the train is approaching him in the opposite direction at a speed which is the sum of the speeds at which both the train are traveling
If the conductor applies brakes on the train, since the platform is a stationary frame of reference. The motion will be observed as a simple decelerationg. he will observe that the force due to the brakes will cause the velocity of the train with respect to the train to decrease
Universal law of gravitation effects all objects alike . There will be a constant force of gravity acting on the train that will keep the train on its tracks. The tracks in turn exert a reaction force on the train. There will not be any affect on the train's motion as such( assuming that the train is moving along the tracks and gravitational force is exactly perpendicular)