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Lostsunrise [7]

3 years ago

14

Light always follows one and the same path traveling back and forth. If a flashlight has a light bulb placed exactly in the foca

l point of its convex lens, it will produce a beam of..
A. converging light rays
B. diverging light rays
C. parallel light rays

1 answer:

Reil [10]3 years ago

5 0

Answer:

converging

.................

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a horse began running due east and covered 25km in 4.0 hours what is the average velocity of the horse

Komok [63]

25km / 4hr = <em>6.25 km/hr east</em>

6 0

3 years ago

Read 2 more answers

Which of the following is an instantaneous speed?

Brilliant_brown [7]

Answer:

A: All of the above

Explanation:

The instantaneous speed of an object is simply the current seed of the object at any given time. The SI unit is m/S and it is a vector quantity.

Therefore, according to the given options, they all have SI units that are consistent with distance and time which makes them all an example of instantaneous speed.

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3 years ago

Free charges do not remain stationary when close together. To illustrate this, calculate the magnitude of the instantaneous acce

ASHA 777 [7]

Answer:

a=2.304×10¹⁶m/s²

Explanation:

Given data

Distance d=2.5 nm=2,5×10⁻⁹m

Mass of proton m=1.6×10⁻²⁷kg

charge of proton q=1.6×10⁻¹⁹C

To find

acceleration a

Solution

Apply the Coulombs Law

$F=k\frac{q_{1}q_{2} }{r^{2} }$

Where k is coulombs constant (k=9×10⁹Nm²/C²)

q=q₁=q₂

r=d

So

$F=k\frac{|q^{2} |}{d^{2} }\\ as \\F=ma\\ma=k\frac{|q^{2} |}{d^{2} }\\a=\frac{k}{m} \frac{|q^{2} |}{d^{2} }\\a=\frac{(9*10^{9} )*(1.6*10^{-19} )^{2} }{(1.6*10^{-27} )*(2.5*10^{-9} )^{2} }\\ a=2.304*10^{16}m/s^{2}$

4 0

4 years ago

One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separat

marin [14]

Answer:

B. 2.77 x $10^{-4}$ N

Explanation:

The required force can be calculated by:

F = $\frac{Kq_{1}q_{2} }{d^{2} }$

Where F is the force between the particles, K is the coulomb's constant (9 x $10^{9}$ $Nm^{2}/C^{2}$ ), $q_{1}$ is the charge on the first particle, $q_{2}$ is the charge on the second particle and $d^{2}$ is the distance between the particles.

So that:

F = $\frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9} }{(0.015)^{2} }$

= $\frac{6.2307*10^{-8} }{(2.25*10^{-4} }$

= 2.7692 x $10^{-4}$

The force between the particles is 2.77 x $10^{-4}$ N.

3 0

3 years ago

Consider this system at equilibrium.

alexandr402 [8]

The given reaction is an exothermic reaction due to the negative amount of enthalpy. In this case, an increase in temperature favors the backward reaction which points to the creation of more products. The expression of K or Q is products over reactants concentration. When this happens, Q becomes smaller then. Hence answer is C and 1.

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3 years ago