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kaheart [24]
2 years ago
14

A student believes she can earn between $5200 and $6250 from her summer job. She knows that she will have to buy four new tires

for her car at $90 each. She estimates her other expenses while she is working at $660. How much can the student save from her summer wages?
Mathematics
1 answer:
ohaa [14]2 years ago
4 0

Answer:

4180 to 5230$

Step-by-step explanation:

1. Lets find the expenses she has to make -> 4*90+660=1020$(4 new tires + other expenses)

2. As her income is not set strictly we can guess the range she can save(More accurate calculations depends on her strict incomes). We have 5200-1020=4180$(if she gets paid 5200$) and 6250-1020= 5230$(if she gets paid 6250$).

3. So the range of savings vary from 4180 to 5230$$.

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natita [175]

Answer:

D. - 1/6

Step-by-step explanation:

M + 2/3 = 1/2

M = 1/2 - 2/3

\frac{1}{2} - \frac{2}{3} = \frac{3}{6} -  \frac{4}{6} = -\frac{1}{6}

6 0
2 years ago
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) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection
RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

C_{(m,n)} = \frac{m!}{n!(m-n)!}

In this question, m = 18, n = 9. So the total number of possibilities is:

T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715

The probability is the number of desired possibilities divided by the number of total possibilities. So

P = \frac{715}{48620} = 0.015 = 1.5%

The probability the he or she will answer correctly is 1.5%

3 0
3 years ago
a man bought a motor at 400,000 Kenyan shillings in January 1999 it depreciated at a rate of 16% per annum if he value it six mo
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The value of the car is January 2003 is  $199,148.54.

<h3>What is the value of the car?</h3>

Depreciation is the rate of decline in the value of an asset with the passage of time.

The exponential equation that can be used to determine the value of the car is:

Value of the car = purchase value(1 - rate of decline)^time

400,000 x (1 - 0.16)^(2003 - 1999)

400,000 x (0.84^4) = $199,148.54

To learn more about depreciation, please check: brainly.com/question/15085226

#SPJ1

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The first 8 on the left in this. umber has a VALUE of 800. :)
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