What is the kinetic energy of a 1500 kg object that is moving at a speed of 71 meters per second
1 answer:
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Answer: A) Deceleration of the car is -6.6667 m/s² while it came to stop.
B) The total distance the car travels is 200 meter during the 10 s period.
Explanation:
Given Data
Initial velocity of the car () = 20.0 m/s
Final velocity of the car () = 0 m/s
Time (in motion) =7.00 s
Time (in rest) =3 s
To find - A) car's deceleration while it came to a stop
B) the total distance the car travels in 10 s
A) The formula to find the deceleration is
Deceleration = (( final velocity - initial velocity ) ÷ Time) (m/s²)
Deceleration = (() - (
)) ÷ time (m/s²)
Deceleration = ( 0.0 - 20 ) ÷ 3 (m/s²)
Deceleration = (- 20) ÷ 3 (m/s²)
Deceleration = - 6.6667 m/s²
(NOTE : Deceleration is the opposite of acceleration so the final result must have the negative sign)
The car's deceleration is - 6.6667 m/s² while it came to a stop
B) The formula to find the distance traveled by the car is
Distance traveled by the car is equals to the product of the speed and time
Distance = Speed × Time (meter)
Distance = 20.0 × 10
Distance = 200 meters
The total distance the car travels during the period of 10 s is 200 meters
Answer:
A) - 1.8 m/s
Explanation:
As we know that whole system is initially at rest and there is no external force on this system
So total momentum of the system must be conserved
so we will have
now plug in all data into above equation
so correct answer is
A) - 1.8 m/s