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valentinak56 [21]
3 years ago
15

A vehicle is being tested using a scan tool. Technician A says that the throttle position (TP) sensor should read between 0 and

1 volt. Technician B says that a factory or factory level scan tool is needed to check for proper voltage and current of the shift solenoids. Which technician is correct?
Engineering
1 answer:
worty [1.4K]3 years ago
5 0

Answer: Non of them.

Explanation:

There are many throttle position sensors voltage check. Computer reference voltage to TP sensor is about 5V. Voltage drop should be less than 0.5 v while TP sensor output to computer is about 0.65v.

When a vehicle is being tested using a scan tool, the only the throttle position (TP) sensor that should read between 0 and 1 volt is the base voltage reading. The reading according to specifications is around 0.05v.

When checking for proper voltage for the opening and closing of the throttle, the voltage rises from 1 volt to a maximum of 5 volts.

Ammeter or multimeter can be used to check for proper voltage and current of the shift solenoids.

We can therefore conclude that both technicians A and B are incorrect. This is, non of them is correct.

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Answer:

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It is auxillary sorry i couldn’t help it happens to the best of us
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Which is not a force of flight?<br> A. Lift<br> B. Drag<br> C. Thrust<br> D. Mass
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A ball is dropped from rest from the top of a cliff that is 30 m high. From ground
trasher [3.6K]

The distance below the top of the cliff that the two balls cross paths is 7.53 meters.

<u>Given the following data:</u>

  • Initial velocity = 0 m/s (since the ball is dropped from rest).
  • Height = 30 meters.

<u>Scientific data:</u>

  • Acceleration due to gravity (a) = 9.8 m/s^2.

To determine how far (distance) below the top of the cliff that the two balls cross paths, we would apply the third equation of motion.

<h3>How to calculate the velocity.</h3>

Mathematically, the third equation of motion is given by this formula:

V^2 = U^2 +2aS

<u>Where:</u>

  • V is the final velocity.
  • U is the initial velocity.
  • a is the acceleration.
  • S is the distance covered.

Substituting the parameters into the formula, we have;

V^2 = 0^2 +2(9.8) \times 30\\\\V^2 = 588\\\\V=\sqrt{588}

V = 24.25 m/s.

<u>Note:</u> The final velocity of the first ball becomes the initial velocity of the second ball.

The time at which the two balls meet is calculated as:

Time = \frac{S}{U} \\\\Time = \frac{30}{24.25}

Time = 1.24 seconds.

The position of the ball when it is dropped from the cliff is calculated as:

y_1 = h-\frac{1}{2} at^2\\\\y_1 = 30-\frac{1}{2} \times 9.8 \times 1.24^2\\\\y_1 = 30-7.53\\\\y_1=22.47\;meters

Lastly, the distance below the top of the cliff is calculated as:

Distance = 30-22.47

Distance = 7.53 meters.

Read more on distance here: brainly.com/question/10545161

4 0
3 years ago
Source 1 can supply energy at the rate of 11000 kJ/min at 310°C. A second Source 2 can supply energy at the rate of 110000 kJ/mi
VladimirAG [237]

Answer:

Source 2.

Explanation:

The efficiency of the ideal reversible heat engine is given by the Carnot's power cycle:

\eta_{th} = 1 - \frac{T_{L}}{T_{H}}

Where:

T_{L} - Temperature of the cold reservoir, in K.

T_{H} - Temperature of the hot reservoir, in K.

The thermal efficiencies are, respectively:

Source 1

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\eta_{th} = 0.466 \,(46.6\,\%)

Source 2

\eta_{th} = 1 - \frac{311.15\,K}{338.15\,K}

\eta_{th} = 0.0798 \,(7.98\,\%)

The power produced by each device is presented below:

Source 1

\dot W = (0.466)\cdot (11000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 85.433\,kW

Source 2

\dot W = (0.0798)\cdot (110000\,\frac{kJ}{min})\cdot (\frac{1\,min}{60\,s} )

\dot W = 146.3\,kW

The source 2 produces the largest amount of power.

8 0
3 years ago
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