Question

The Grand Canyon is 1800 meters deep at its deepest point. A rock is dropped from the rim above this point. Write the height of the rock as a function of the time in seconds. How long will it take the rock to hit the canyon floor?

Answer 1

Answer:

Explanation:

Given

height of grand canyon is $h=1800\ m$

Rock is dropped i.e. initial velocity is zero

$u=0$

Using Equation of motion

$h=ut+\frac{1}{2}at^2$

h=height

u=initial velocity

a=acceleration

t=time

here a=acceleration due to gravity

$1800=0+\frac{1}{2}\times 9.8\times t^2$

$t^2=\frac{2\times 1800}{9.8}$

$t=19.166\ s$