Answer:
10/9
Explanation:
First, let's convert 1/3 and 7/9 so that the have the same denominator. To do this let's find the least common multiple of 3 and 9.
List the multiples of 3 and 9:
3: 3, 9
9: 9
They have a least common multiple of 9
We need to convert 1/3 so it has a denominator of 9:
1/3*3/3 (we can multiply it by 3/3 because any number over itself is 1) = 3/9
s-3/9=7/9
Add 3/9 to both sides to isolate s
s=10/9
Answer:
The energy levels in an atom are similar to the rungs of a ladder, but they get closer together as they get farther from the nucleus. For an electron to move from one energy level to the next higher level, it must gain the right amount of energy. If less than that amount is available, the electron stays where it is.
Explanation:
Hope this helped! Goodluck on your test or whatever you're doing! Stay safe ♥♥♥
Write an balance the equation
Na2O + H2O -> 2 NaOH
Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.
Na = 23
O=16
H=1
Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40
For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g
120 g Na2O x 80g NaOH / 62g Na2O=
154.8 g NaOH
Answer:
14,938 tablets.
Explanation:
WE divide:
1.21 kg / 81 mg
1.21 kg = 1,210 g = 1.210,000 mg.
So it is 1,210,000 / 81
= 14,938 tablets.
Answer:
OPTION C is correct
C) 1.07 g
Explanation:
CaCl2(aq) + 2 AgNO3(aq) → 2 AgCl(s) + Ca(NO3)3(aq)
But we know molarity molarity= number of moles of solute/ volume of the solution
M= n/V
From the equation above
number of moles of Cacl2 = (37.5 ×0 .100 × 10^-3) = 0.00375 moles.
Then
1 mole of Cacl2 yields 2 moles of Agcl2
0.00375 moles of Cacl2 will produce let say Y.
Y= (0.00375 ×2)/1
= 0.0075 moles.
Number of moles of Agcl2 = mass /molar mass of Agcl
Molar mass of Agcl = 178
Then mass = 178 ×0.0075 = 1.047
Therefore, the mass of agcl precipitate is
1.07 g
