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Sloan [31]
3 years ago
9

When C2H6(g) reacts with O2(g) according to the following reaction, 1.43×103 kJ of energy are evolved for each mole of C2H6(g) t

hat reacts. Complete the following thermochemical equation.
2C2H6(g) + 7O2(g)---------->4CO2(g) + 6H2O(g) DeltaH = _____kJ
Chemistry
1 answer:
dezoksy [38]3 years ago
8 0

Answer:

-2.86x10³ kJ

Explanation:

The enthalpy of a reaction (ΔH) is defined as the heat produced or consumed by a reaction. In the reaction:

2 C₂H₆(g) + 7 O₂(g) → 4 CO₂(g) + 6 H₂O(g)

The ΔH is the heat envolved in the reaction per 2 moles of C₂H₆. 1.43x10³ kJ are involved when 1 mole reacts. Thus, when 2 moles react, involved heat is:

1.43x10³ kJ ₓ 2 = <em>2.86x10³ kJ</em>. As the reaction is a combustion reaction (Produce CO₂ and H₂O), the heat involved in the reaction is <em>PRODUCED, </em>that means ΔH is negative, <em>-2.86x10³ kJ</em>

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svlad2 [7]

Lower flammable limit means the lowest concentration of a material that will propagate a flame.

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It is an atmosphere that may expose employees to risk of death, incapacitation, impairment of ability to self-rescue, injury, or acute illness from one or more of following causes

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6 0
1 year ago
4HCI + O2 =2H20 + Cl2
Sergio039 [100]

The rate of the backward reaction increases

Explanation:

It is evident that if the reaction is left to proceed spontaneously, the forward reaction is favored because it results in a decrease in pressure in the system (The total reactants have 5 moles and the products have 3 in total).

Increasing H₂O concentration is then reaction, therefore, stymies the forward reaction and favors the reserves reaction. This is because the reverse reaction will lead to reduced pressure.

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Do the molecules in a desk have energy?
Harrizon [31]
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6 0
3 years ago
1. Marisa determined the melting point of a substance to be 24.5C. Find the percent error of her measurement if the actual melti
USPshnik [31]

Answer:

\%\ Error = 21.5\%

Explanation:

Given

Measured = 24.5

Actual = 31.2

Required

Determine the percentage error

First, we need to determine the difference in the measurement

Difference = |Actual - Measured|

Difference = |31.2 - 24.5|

Difference = |6.7|

Difference = 6.7

The percentage error is calculated as thus:

\%\ Error = \frac{Difference * 100\%}{Actual}

\%\ Error = \frac{6.7 * 100\%}{31.2}

\%\ Error = \frac{670\%}{31.2}

\%\ Error = 21.4743589744\%

\%\ Error = 21.5\% <em>approximated</em>

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