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svlad2 [7]
3 years ago
14

An inclined plane of length 12m is used to pull a load of 3000N to height of 3m by applying an effort of 1000N. Calculate its MA

, VR and efficiency. Also, find the work done in the machine
Physics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

MA  = 4

VR = 3

e = 0.75 or 75%

work = 12000 [J]

Explanation:

The mechanical advantage in an inclined plane is defined as the relationship between the length of the inclined plane and the height of the plane with respect to the ground.

MA = L/h

MA = 12/3 = 4

Now the real advantage can be calculated as the relationship between the weight of the body and the force being applied.

VR = W/F

VR = 3000/1000

VR = 3

Efficiency can be calculated as the relationship between the real mechanical advantage over the ideal mechanical advantage.

e = VR/MA

e = 3/4

e = 0.75 or 75%

The work is defined as the product of the force by the distance, therefore we have:

work = F*d

work = 1000*12

work = 12000 [J]

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Answer:

W = 46 J

Explanation:

We need to find the angle between the two vectors Force vector and displacement vector.

First we will find the angle α of the force vector

tan\alpha =\frac{1}{8} \\\\\\alpha =7.125 deg\\

Then we find the angle β of the displacement vector

tan\beta=\frac{2}{6} \\\\beta = 18.43 deg\\

With these two angles we can find the angle between the two vectors

∅ = α + β = 25.56 deg

The definition of work is given by the expression

W=F*d*cos (theta)

The absolute value of F will be:

F=\sqrt{8^{2}+1^{2}  } \\F= 8.06 N

The absolute value of d will be:

d=\sqrt{(6 )^{2}+(2)^{2}  } \\d= 6.32m\\

Now we have:

W=8.06*6.32*cos(25.56)\\W=46 J

4 0
3 years ago
What happened to the weight of an object when it is taken from Earth to the Moon? why?<br>​
Sholpan [36]

Answer:

the weight of the object decreases when it is taken from the Earth to the Moon

Explanation:

The weight of an object is defined as the product of the mass of the object with the acceleration due to gravity of the Planet.

W =mg

where,

W = weight of the object

m = mass of the object

g = acceleration due to gravity on the planet

The mass of an object remains constant everywhere in the universe. Therefore, the weight is directly proportional to the value of acceleration due to gravity.

The value of acceleration due to gravity on the Moon is lesser than its value on the Earth.

<u>Hence, the weight of the object decreases when it is taken from the Earth to the Moon </u>

6 0
3 years ago
Could you explain to me how the soccer collects kinetic energy when its kicked?
aniked [119]
FOR THAT YOU NEED TO UNDERSTAND WHAT ACTUALLY KINETIC ENERGY IS.
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3 years ago
A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is
LenaWriter [7]

Answer:

0.2

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F= BIL sin©

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B=3/15

B= 0.2

8 0
2 years ago
Photons of wavelength 65.0 pm are Compton-scattered from a free electron which picks up a kinetic energy of 0.84 keV from the co
ElenaW [278]

Answer:

λ  = 65.6 pm

Explanation:

Given that

λo = 65 pm

The initial energy of the electron

E_o=\dfrac{hC}{\lambda_0 }

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E_o=\dfrac{hC}{\lambda_0 }

E_o=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{65\times 10^{-12}}

E_o=3.05\times 10^{-15}\ J

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Given that kinetic energy KE= 0.84 KeV

Therefore the final energy

E= Eo - KE

E = 19.06 - 0.84 KeV

E= 18.22 KeV

The wavelength  λ can be find as

E=\dfrac{hC}{\lambda}

\lambda=\dfrac{hC}{E}

\lambda=\dfrac{6.67\times 10^{-34}\times 3\times 10^8}{19.06 \times 10^3\times 1.6\times 10^{-19}}

λ = 6.56 x 10⁻¹¹ m

λ  = 65.6 pm

3 0
3 years ago
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