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snow_lady [41]
3 years ago
5

Materials that do not allow electricity to flow through them are called

Physics
1 answer:
eimsori [14]3 years ago
6 0
These substances are called insulators. We also have a class of substance called a semi-conductor. They share many properties with insulators. You can sometimes see them on telephone poles.
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What is the weight of a person with a massa of 80kg
Archy [21]
784 Newtons or 176.37 lbs
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3 years ago
You need to produce a set of cylindrical copper wire 3.5 m long that will have a
vazorg [7]

Solution :

We know, resistance is given by :

R = \dfrac{\rho l}{A}

A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2

Now, we know mass of wire is given by :

Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram

Hence, this is the required solution.

8 0
3 years ago
What is an independent variable
snow_tiger [21]

Answer:

A variable (often denoted by x ) whose variation does not depend on that of another.

Explanation:

8 0
3 years ago
A football player with a mass of 88 kg and a speed of 2.0 m/s collides head-on with a player from the opposing team whose mass i
Ket [755]

Answer:

Speed of another player, v₂ = 1.47 m/s

Explanation:

It is given that,

Mass of football player, m₁ = 88 kg

Speed of player, v₁ = 2 m/s

Mass of player of opposing team, m₂ = 120 kg

The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :

m_1v_1+m_2v_2=(m_1+m_2)V

V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.

v_2=-\dfrac{m_1v_1}{m_2}

v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}

v_2=-1.47\ m/s

So, the speed of another player is 1.47 m/s. Hence, this is the required solution.

7 0
4 years ago
How many milliliters are in 1.2 L ( 1 mL= 0.001 L
alisha [4.7K]
1200 mL

1.2L*1000mL/1L=1200mL (after canceling alike units)
Hope this helps:)
4 0
4 years ago
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