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alexira [117]
2 years ago
12

Tearing of paper is said to be a change that cannot be reversed. What about paper recycling? Explain.

Physics
1 answer:
Step2247 [10]2 years ago
6 0

Answer:

Recycling of paper cannot be reversed thus making it an irreversible change

Explanation:

When we recycle paper an entirely new product can be made which cannot be changed back to paper

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Explanation:

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How long will it take you to pass a truck at 60 mph with oncoming traffic?
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Find our the total distance between those 2 womens after 100 seconds. Refer the image for the full question ASAP. Give me a comp
diamong [38]
<h3>Given</h3>

\small\bf\red{First\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 15m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

\small\bf\green{Second\: Women}\begin{cases}\sf{Initial\: Velocity\: =\: 20m/s}\\\sf{Time\: Taken\: = 100\: seconds}\end{cases}

<h3>To Find</h3>

\:\:\:\:\bullet\:\:\sf{Distance \: between \:them \:after \:{\sf{\blue{100 \:seconds}}}} \\

<h3>Solution </h3>

\\→\:\:\:\sf Distance\: travelled \:by \:1st \:women\: = \: Velocity \times Time\:taken

→\:\:\:\sf 15 \times 100

→\:\;\:\sf 1500m

→\:\:\:\sf s_{1} = {\sf{\red{1500m}}} \\ \\

\Rightarrow\:\:\:\sf Distance \:travelled \:by\: 2nd \:women\: = \: Velocity \times Time\:taken

\Rightarrow\:\:\:\sf 20 \times 100

\Rightarrow\:\:\:\sf  2000m

\Rightarrow\:\:\:\sf s_{2} = {\sf{\purple{2000m}}} \\ \\

\small{\underline{\bf{Now, \:Distance \:between \:them\: =\: s_{2} - s_{1}}}_{}}

\hookrightarrow\:\:\:\sf 2000 - 1500

\hookrightarrow\:\:\:\bf \pink{500m} \\ \\

{\underline{\bf{Hence, }}}

Total Distance between them after \bf{100 \:seconds} is \bf\orange{500m}

3 0
3 years ago
An electrically neutral model airplane is flying in a horizontal circle on a 2.0-m guideline, which is nearly parallel to the gr
amm1812

Answer:

q=3.5*10^-4

Explanation:

<u>concept:</u>

The force acting on both charges is given by the coulomb law:

F=kq1q2/r^2

the centripetal force is given by:

Fc=mv^2/r

The kinetic energy is given by:

KE=1/2mv^2

<u>The tension force:</u>

<u><em>when the plane is uncharged </em></u>

T=mv^2/r

T=2(K.E)/r

T=2(50 J)/r

T=100/r

<u><em>when the plane is charged </em></u>

T+k*|q|^2/r^2=2(K.E)charged/r

100/r+k*|q|^2/r^2=2(53.5 J)/r

q=√(2r[53.5 J-50 J]/k)                                          √= square root on whole

q=√2(2)(53.5 J-50 J)/8.99*10^9

q=3.5*10^-4

5 0
3 years ago
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