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Afina-wow [57]
3 years ago
10

The mechanical advantage of any machine is: A) the efficiency of the machine B) the work done by the machine C) the ratio of the

work done by the machine to the work expended on it D) the ratio of the force exerted by the machine to the force applied to E) the ratio of the force applied to the machine to the force exerted by it it
Physics
1 answer:
lianna [129]3 years ago
7 0

Answer:

Option D) the ratio of the force exerted by the machine to the force applied

Explanation:

The measure of the amplification of the force applied to a mechanical device or a measure of the force exerted by a mechanical device.

The input of the tool or machine is then conserved and the forces are trade off against motion to achieve a required level of amplification.

Therefore, only option c. complies with it.

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What is the range of a ball thrown horizontally at 12 m/s if its time of flight is 3.0 s?
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Use Hooke's Law to determine the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters.
ladessa [460]

Answer:

Work Done = 67.5 J

Explanation:

First we find the value of spring constant (k) using Hooke's Law. Hooke's is formulated as:

F = kx

where,

F = Force Applied = 450 N

k = Spring Constant = ?

x = Stretched Length = 30 cm = 0.3 m

Therefore,

450 N = k(0.3 m)

k = 450 N/0.3 m

k = 1500 N/m

Now, the formula for the work done in stretching the spring is given as:

W = (1/2)kx²

Where,

W = Work done = ?

k = 1500 N/m

x = 70 cm - 40 cm = 0.3 m

Therefore,

W = (1/2)(1500 N/m)(0.3 m)²

<u>W = 67.5 J</u>

3 0
3 years ago
Paper clips and screws are can be picked up by a magnetic because they contain a high amount of ?
ch4aika [34]

Answer:

D

Explanation:

5 0
3 years ago
What mass of electrons would be required to just neutralize the charge of 4.8 g of protons?
suter [353]
Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of q=1.6 \cdot 10^{-19} C, and a mass of m_p = 1.67 \cdot 10^{-27}kg. So, the number of protons is
N_p =  \frac{M}{m_p}= \frac{0.0048 kg}{1.67 \cdot 10^{-27}kg}=2.87 \cdot 10^{24} And so the total charge of these protons is Q_p = qN_p = (1.6 \cdot 10^{-19}C)(2.87 \cdot 10^{24})=4.6\cdot 10^5 C

So, the neutralize this charge, we must have N_e electrons such that their total charge is
Q_e = -4.6 \cdot 10^5 C
Since the charge of each electron is q_e = -1.6 \cdot 10^{-19}C, the number of electrons needed is
N_e =  \frac{Q_e}{q}= \frac{-4.6 \cdot 10^5 C}{-1.6 \cdot 10^{-19}C}=2.87 \cdot 10^{24}
which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is m_e=9.1 \cdot 10^{-31}kg, the total mass of electrons should be
M_e = N_e m_e = (2.87 \cdot 10^{24})(9.1 \cdot 10^{-31}kg)=2.6 \cdot 10^{-6}kg
6 0
3 years ago
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