Answer:
the magnitude of the total electric field is 25 V/m
Explanation:
Given data
point above = 0.5 m
charges = 18 V/m
to find out
the magnitude of the total electric field
solution
the magnitude of the total electric field is 25 V/m because number is less than the twice magnitude of field by every charge and the horizontal component in electric field by every charge cancel out and vertical component in field added together
Answer:
I believe it would be Direction B
Explanation:
After passing A, gravity would pull the ball downwards
1. calculate the value of acceleration that objects gains in that period of time
•calculating acceleration
5.50 = 1/2at^2
5.50*2/t^2 = a
11.00/0.657 = a
16.74=a
now you got the acceleration
2. you have laws of gravitation for that
g = Gm/r^2
where g is the acceleration value
16.74 = 6.754*10^-11 × m/ 6.28*10^4
105.14*10^4 /6.754*10-11 = m
15.567*10^15 = m
that would be the mass of the planet ...
Answer:
Explanation:
We know that the frequency of the nth harmonic is given by 
, where 
is the fundamental harmonic. Since we have the values of two consecutive frequencies, we can do:
Which for our values means (we do not need the value of <em>n</em>, that is, which harmonics are the frequencies given):
Now we turn to the formula for the vibration frequency of a string (for the fundamental harmonic):
So the tension is:
Which for our values is:
