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Ray Of Light [21]
3 years ago
15

Which method is used to deliver heat in most central heating systems?

Physics
2 answers:
Wewaii [24]3 years ago
5 0
Theu use convection currents to blow the air aroubd the house
inessss [21]3 years ago
4 0
The right  answer is B. hope this helps you :)
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Anyone please help me with this question ASAP
Katyanochek1 [597]

Answer:

increases

Explanation:

it would have to work harder to get to two points together

7 0
3 years ago
An astronaut on the moon drops a feather from rest (v = 0). The acceleration due to gravity is 1.67 m/s​ 2​ . If the feather beg
olga_2 [115]

Given :

Initial velocity , u = 0 m/s .

Acceleration due to gravity on moon , g_m=1.67\ m/s^2 .

Height , h = 2 m .

To Find :

Final position after falling for 1.5 seconds .

Solution :

We know , by equation of motion :

s=ut+\dfrac{at^2}{2}

Here , a = g_m .

So , equation will transform by :

s=ut+\dfrac{g_mt^2}{2}\\\\s=0+\dfrac{1.67\times 1.5^2}{2}\ m\\\\s=1.88\ m

Therefore , the height form moon's surface is 1.88 m .

Hence , this is the required solution .

6 0
3 years ago
Which best compares AC and DC?
Naily [24]
Yea im pretty sure its B
5 0
3 years ago
Read 2 more answers
Please!! List three things that can affect solubility.
Dennis_Churaev [7]
Nature of the solute and solvent, Temperature, and Pressure all affect solubility.
7 0
3 years ago
What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n
Yuri [45]

Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  wavelength is  \lambda  =  622 nm

Explanation:

  From the question we are told that

    The distance of the slit to the screen is  D  = 5 \ m

    The order of the fringe is m  =  6

     The distance between the slit is  d = 0.9 \ mm  =  0.9 *10^{-3} \ m

    The fringe distance is  Y =  1.9 \ cm  =  0.019 \ m

Generally the for a dark fringe the fringe distance is  mathematically represented as

        Y  = \frac{[2m  - 1 ] *  \lambda *  D  }{2d}

=>     \lambda  =  \frac{Y *  2 *  d }{[2*m  -  1] *  D}

substituting values

=>      \lambda  =  \frac{0.019 *  2 *  0.9*10^{-3} }{[2*6  -  1] *  5}

=>     \lambda  =  6.22 *10^{-7} \ m

       \lambda  =  622 nm

8 0
3 years ago
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