Explanation:
It is known that the relation between pH and 
is as follows.
pH = ![pK_{a} + log \frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
and, 
Hence, first we will calculate the value of as follows.
= 
= 4.75
Now, we will calculate the value of pH as follows.
pH = ![pK_{a} + log \frac{[\text{sodium acetate}]}{\text{acetic acid}}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5B%5Ctext%7Bsodium%20acetate%7D%5D%7D%7B%5Ctext%7Bacetic%20acid%7D%7D)
= 
= 4.75 + (-0.677)
= 4.07
Therefore, we can conclude that the pH of given solution is 4.07.
Answer:
The answer to your question is:
1.- CO
2.- 0.414 moles of CO2
Explanation:
Data
2CO + O2 ⇒ 2CO2
CO = 0.414 moles
O2 = 0.418
Process
theoretical ratio CO/O2 = 2/1 = 1
experimental ratio CO/O2 = 0.414/0.418 = 0.99
Then the limiting reactant is CO
2.-
2 moles of CO --------------- 2 moles of CO2
0.414 moles of CO --------- x
x = (0.414 x 2) / 2
x = 0.414 moles of CO2
<span>If energy is released, the reaction is exothermic. If energy is absorbed, the reaction is endothermic. Since heat is being absorbed in this reaction (to break down H2O into H2 and O), the reaction is endothermic.</span>
Answer: The final volume of this solution is 0.204 L.
Explanation:
Given: Molarity of solution = 2.2 M
Moles of solute = 0.45 mol
Molarity is the number of moles of solute present divided by volume in liters.
Substitute the values into above formula as follows.
Thus, we can conclude that the final volume of this solution is 0.204 L.
The correct answer is: [B]:
___________________________________________________________
" N₂ (g) + 3 H₂ (g) → 2 NH₃ <span>(g) " .
___________________________________________________________
Note of interest:
___________________________________________________________
This particular reaction is known as the "</span>Haber process" .
___________________________________________________________
