Accuracy is when you hit as close as to the target as you can and precision is when you are on point
Answer:
About 16.1 grams of oxygen gas.
Explanation:
The reaction between magnesium and oxygen can be described by the equation:

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.
Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:
- Convert grams of MgO to moles of MgO.
- Moles of MgO to moles of O₂
- And moles of O₂ to grams of O₂.
The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.
Dimensional analysis:

In conclusion, about 16.1 grams of oxygen gas was reacted.
You will obtain the same result if you compute with the 24.4 grams of Mg instead:

Molar volume at STP = 22,4 L
1 mole -------------- 22,4 L
x mole -------------- 11,2 L
x = 11,2 / 22,4
x = 0,5 moles of N2
1 mole --------------- 6,02.10²³ molecules
0,5 moles ------------ y molecules
y = 0,5 . 6,02.10²³
y = 3,01.10²³ molecules
Answer:
grams/mol of carbon is needed to react with hydrogen gas to produce 59.8 grams of acetylene (C2H2)
Explanation:
The molecular weight of acetylene is 26.04 g/mol
Molecular weight of carbon is equal to 12.011 g/mol
Two carbon atom produces one acetylene molecule.
Thus, 2 * 12.011 g/mol of carbon is used to produce 26.04 g/mol of acetylene,
Amount of carbon required to produce 59.8 grams of acetylene
grams/mol
grams/mol of carbon is needed to react with hydrogen gas to produce 59.8 grams of acetylene (C2H2)