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hoa [83]
3 years ago
13

What did Bohr’s model of the atom do that Rutherford’s model did not?

Chemistry
2 answers:
Dafna1 [17]3 years ago
5 0

Answer:

The last option

Explanation:

The Bohr model was an attempt to explain atomic hydrogen's spectrum. This was done by establishing energy levels of separate electron orbits in the atom.Thos model was followed by the Schrödinger model.

scoundrel [369]3 years ago
3 0

Answer:

It focused on the location and energy of electrons.

Explanation:

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Use the periodic table to identify the element with the electron configuration 1s²2s²2p⁴. Write its orbital diagram, and give th
natta225 [31]

Answer:

1. Orbital diagram

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

2. Quantum numbers

  • <em>n </em>= 2,
  • <em>l</em> = 1,
  • m_{l} = 0,
  • m_{s} = +1/2

Explanation:

The fill in rule is:

  • Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
  • Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
  • Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).

So, the orbital diagram of given element is as below and the sixth electron is marked between " "

2p⁴   ║ ↑↓ ║  "↑"  ║   ↑

2s²    ║ ↑↓ ║

1s²     ║ ↑↓ ║

The quantum number of an electron consists of four number:

  • <em>n </em>(shell number, - 1, 2, 3...)
  • <em>l</em> (subshell number or  orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
  • m_{l} (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
  • m_{s} (spin of electron), either -1/2 or +1/2

In our case, the electron marked with " " has quantum number

  • <em>n </em>= 2, shell number 2,
  • <em>l</em> = 1, subshell or orbital <em>p,</em>
  • m_{l} = 0, 2nd "box" in the range -1, 0, 1
  • m_{s} = +1/2, single electron always has +1/2
3 0
3 years ago
If a bullet travels at 407.0 m/s, what is its speed in miles per hour? Number click to edit mi/h For the same bullet travelling
kaheart [24]

Answer : The speed in miles per hour is 22 mile/hr.

The speed in yard per min is 26617.8 yard/min

Explanation :

The conversion used for meters to miles is:

1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}

The conversion used for second to hour is:

1s=\frac{1}{60}min\times \frac{1hr}{60min}

The conversion used for meter per second to mile per hour is:

1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.

1m/s=2.2mile/hr

So, 407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr

Therefore, the speed in miles per hour is 22 mile/hr.

The conversion used for meter to yard

1m = 1.09 yard

The conversion used for second to hour is:

1s=\frac{1}{60}min

The conversion used for meter per second to mile per hour is:

1m/s=\frac{1.09yard}{frac{1}{60min}}

1m/s=65.4yard/min

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min

1m/s=65.4yard/min

So, 407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min

Therefore, the speed in yard per min is 26617.8 yard/min

7 0
3 years ago
8. Thermal Energy is?
Burka [1]

Thermal energy is the sum of the kinetic and potential energy of all the particles in an object. The figure shows that if either potential or kinetic energy increases, thermal energy increases.

hope it really helps...!!!

4 0
2 years ago
How do you convert ounces to grams
jok3333 [9.3K]
However many ounces you have, just multiply that by 28.34952. The answer to that is the conversion. so 5 ounces is 141.7476. Proof below.

4 0
3 years ago
Read 2 more answers
Write 0.000443200 to two significant figures
Tju [1.3M]
0.00044


Zeros to the right of the decimal place are not significant UNLESS they are found in between or after a non-zero number, therefore, we take the 3200 away because those ARE significant so then after you round your answer (if needed) you're left with only two numbers that are significant.
6 0
3 years ago
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