Question

To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN?

Answer 1

Answer:

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN

Explanation:

Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.

In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

In a solution it is fulfilled:

Ci* Vi = Cf* Vf

where:

• Ci: initial concentration
• Vi: initial volume
• Cf: final concentration
• Vf: final volume

In this case:

• Ci= 1.40 M
• Vi= 20 mL
• Cf= 0.088 M
• Vf= ?

Replacing:

1.40 M* 20 mL= 0.088 M* Vf

Solving:

$Vf=\frac{1.40 M* 20 mL}{0.088 M}$

Vf= 318.18 mL

To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN