The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.
<h3>
Molecular mass of potassium carbonate</h3>
The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;
M = K₂CO₃
M = (39 x 2) + (12) + (16 x 3)
M = 138 g
mass of carbon in potassium carbonate, K₂CO₃ is = 12 g
The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;
138 g ------------ 12 g of carbon
2.25 g ------------ ?
= (2.25 x 12) / 138
= 0.196 g
Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.
Learn more about potassium carbonate here: brainly.com/question/27514966
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<u>Given:</u>
Initial velocity (v1) = 0 m/s
Final velocity (v2) = 30 m/s
Acceleration (a) = 6.1 m/s2
<u>To determine:</u>
The time (t) taken to reach the final speed
<u>Explanation:</u>
Use the relation:
Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)
t = (v2-v1)/a = 30-0/6.1 = 4.92 s
Ans: Time taken is around 4.9 s
1.6456 x 10^3 (ten to the third power)
