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kolbaska11 [484]
3 years ago
9

When work is done on a system, what changes? inertia energy momentum

Physics
1 answer:
matrenka [14]3 years ago
8 0
The answer is energy :)
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If a sheep is running at 3.0 m/s with a mass of 60 kg what is its kinetic energy​
borishaifa [10]

Answer:270joules

Explanation:KE = 1/2mv^2

KE = 1/2(60kg)(3.0)^2 = 270 Joules

8 0
3 years ago
A toy doll and a toy robot are standing on a frictionless surface facing each other. The doll has a mass of 0.2 kg, and the robo
Natali5045456 [20]

Answer:

<h3>1.43m/s²</h3>

Explanation:

According to newtons second law.

F = mass * acceleration

If the doll has a mass of 0.2 kg, and the robot has a mass of 0.5 kg, the resulting mass will be 0.7kg

Force applied = 1N

acceleration = Force/mass

Substitute the values and get acceleration

acceleration = 1/0.7

acceleration = 1.43m/s²

Hence the magnitude of the acceleration of the robot is 1.43m/s²

3 0
3 years ago
There is a 90 kg woman attached at the end of a bungee cord (k = 35 N/m) that is experiencing simple harmonic motion. How long d
Cloud [144]

Answer:

The value is T  =10.1 \ s

Explanation:

From the question we are told that

    The mass of the woman is  m  = 90 \  kg  

    The spring constant of the bungee cord is  k  =  35 \  N/  m

Generally the period of the oscillation (i,e time taken to complete on  cycle ) is mathematically represented as

            T  = 2 \pi *  \sqrt{ \frac{m}{k} }

=>      T  = 2 * 3.142  *  \sqrt{ \frac{90 }{ 35} }

=>      T  =10.1 \ s

3 0
3 years ago
Two long wires hang vertically. wire 1 carries an upward current of 1.60
charle [14.2K]
3.00 is my correct answer this is what my teacher told me.thanks
7 0
3 years ago
The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t
marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

I = 9.7 \times 10^{37} kg m^2

Explanation:

Since Earth is considered as solid sphere

So we will have

I = \frac{2}{5}M_eR_e^2

so we will have

I = \frac{2}{5}(5.97 \times 10^{24})(6.371 \times 10^6)^2

so we have

I = 9.7 \times 10^{37} kg m^2

3 0
3 years ago
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