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Vilka [71]
3 years ago
5

Which of the following statements is true?

Physics
2 answers:
vekshin13 years ago
8 0
Your answer is D I took this test
sergejj [24]3 years ago
6 0

Answer:

1.) Since the sun uses it's own hydrogen to create energy, it will eventually run out of fuel and burn out.

Explanation:

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What does the term "heat capacity" refer to?
kenny6666 [7]

Answer:

option C is correct

.............,

4 0
3 years ago
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What is the electromagnetic spectrum
riadik2000 [5.3K]
"Generally, electromagnetic<span> radiation is classified by wavelength into radio wave, microwave, terahertz (or sub-millimeter) radiation, infrared, the visible region that is perceived as light, ultraviolet, X-rays and gamma rays. The behavior of </span>EM<span> radiation depends on its wavelength."
Source: wikipedia.org</span>
5 0
4 years ago
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A block lying on an inclined plane has a weight of 50 N. It just begins to slide down when the inclination of plane with the hor
hjlf

Answer:

μ = tanθ = tan30 = 0.58

Explanation:

μ = force parallel/force perpendicular = mgsinθ/mgcosθ = tanθ

5 0
3 years ago
For a proton in the ground state of a 1-dimensional infinite square well, what is the probability of finding the proton in the c
Butoxors [25]

Answer:

The probability of finding the proton at the central 2% of the well is almost exactly 4%

Explanation:

If we solve Schrödinger's equation for the infinite square well, we find that its eigenfunctions are sinusoidal functions, in particular, the ground state is a sinusoidal function for which only half a cycle fits inside the well.

let L be the well's length, the boundary conditions for the wavefunction are:

\psi(0) = \psi(L) =0

And Schrödinger's equation is:  

- \frac{\hbar^2}{2m} \frac{d^2\psi}{dx^2} = E\psi

The solution to this equation are sines and cosines, but the boundary conditions only allow for sine waves. As we pointed out, the ground state is the sine wave with the largest wavelength possible (that is, with the smallest energy).

\psi_0(x)=\sqrt[]{\frac{2}{L} }\, \sin(\frac{\pi x}{L} )\\

here the leading constant is just there to normalise the wavefunction.

Now, if we know the wavefunction, we can know what the probability density function is, it is:

f_X(x) = |\psi|^2

So in our case:

f_X(x) = \frac{2}{L} \sin^2(\frac{\pi x}{L})

And to find the probability of finding the particle in a strip at the centre of the well of width 2% of L we only have to integrate:

P(X \in [0.49 L, 0.51L ])= \int\limits^{0.49L}_{0.51L } {\frac{2}{L} \sin^2(\frac{\pi x}{L})} \, dx

If we do a substitution:

x = u \, L

We get the integral:

\int\limits^{0.49}_{0.51 } 2\,  \sin^2(\pi u)} \, du

This integral can be computed analytically, and it's numerical value is .0399868, that is, almost a 4% probability.

5 0
3 years ago
Gold has a density of 19.32 g/cm 3 . If you cut a piece of gold in half, the density of each piece will be
maksim [4K]

Answer:

See Explanation

Explanation:

The density of a substance is an intrinsic property. Intrinsic properties are properties that are characteristic of a material. It does not depend on the amount of substance present.

Since density is an intrinsic or intensive property, If you cut a piece of gold in half, the density of each piece will still be 19.32 g/cm 3 because density does not depend on the size of the gold piece.

3 0
3 years ago
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