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3 years ago

5

Which of the following statements is true?

2 answers:

vekshin13 years ago

8 0

Your answer is D I took this test

sergejj [24]3 years ago

6 0

Answer:

1.) Since the sun uses it's own hydrogen to create energy, it will eventually run out of fuel and burn out.

Explanation:

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The speed of light in a solid is 1.24 x 108 m/s. <br> Calculate the index of refraction

Dahasolnce [82]

Answer:

125

Explanation:

7 0

3 years ago

A draft is made of a plastic block with a density of 650kg/m^3, and its dimensions are 2.0mx3.0mx5.0m ,what is the raft's appare

mixas84 [53]

Weight in water = mass of block - mass of volume of displaced water

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3 years ago

A large flat block of mass 7 m rests on a level, smooth tabletop (µk ≈ 0). On top of it is a much smaller block of mass m, with

mariarad [96]

Answer:

3. µs g /7

Explanation:

The largest Force appear when the maximal friction Force is required.

Second Newton law for the small block:

$F_friction=u_s*N=u_s*(mg)$

$F-F_friction=ma$

$F-u_s*(mg)=ma$

Second Newton law for the Big Block:

$F_friction=7ma$

$u_s*(mg)=7ma$

$a=u_s*g/7$

8 0

3 years ago

What is one advantage of using primary source when doing research on an experiment

kenny6666 [7]

the benefit of direct contact, through a survey or interview

6 0

3 years ago

The gravitational force of attraction be-

Sliva [168]

Answer:

2.15 m

Explanation:

Newton's Law of Universal Gravitation:

$\displaystyle F_g = G \frac{m_1 m_2}{r^2}$

$\displaystyle F_g$ is the gravitational force of attraction

$\displaystyle G$ is the universal gravitational constant

$m_1$ and $m_2$ are the two masses of the two objects

$\displaystyle r$ is the distance between the centers of the two objects.

List the known values:

$\displaystyle F_g = 3.47 \cdot 10^-^8 \ \text{N}$
$\displaystyle G = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2}$
$\displaystyle m_1 = 44.8 \ \text{kg} \\ m_2 = 53.9 \ \text{kg}$
$\displaystyle r =\ ?$

Plug these values into the equation:

$\displaystyle 3.47 \cdot 10^-^8 \ \text{N} = 6.673 \cdot 10^-^1^1 \ \frac{Nm^2}{kg^2} \frac{(44.8 \ \text{kg})(53.9 \ \text{kg})}{r^2}$

Notice that the units $\displaystyle \text{N}$ , $\displaystyle \text{kg}^2$ , and $\displaystyle \text{m}$ cancel out. We are left with the unit $\displaystyle \text{m}$ for radius r.

Get rid of the units to make the problem easier to read.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(44.8)(53.9) \ }{r^2}$

Multiply the masses together.

$\displaystyle 3.47 \cdot 10^-^8= 6.673 \cdot 10^-^1^1 \ \frac{(2414.72)}{r^2}$

Multiply the gravitational constant and the masses together.

$\displaystyle 3.47 \cdot 10^-^8= \frac{1.61134265\cdot 10^-^7}{r^2}$

Solve for $r^2$ by dividing both sides by 3.47 * 10^(-8) and moving $r^2$ to the left.

$\displaystyle r^2 = \frac{1.61134265\cdot 10^-^7}{3.47\cdot 10^-^8}$
$r^2 = 4.64363876$

Take the square root of both sides.

$r=2.154910383$

The students are sitting about 2.15 m apart from each other.

4 0

2 years ago